Welcome to Mentor for Bank Exams. Here I am
sharing the Quantitative
Aptitude questions with detailed explanation. These questions
can be helpful for the upcoming bank exams, insurance exams and other
competitive exams. Kindly make use of these!!!
Directions (1 – 5): Study the following table and Pie Chart
carefully and answer the questions that follow—
FDI in Indian States During the Year
19992000
States

UP

Delhi

Karnataka

Maharashtra

Kerala

MP

AP

FDI (in
Rs.Crores)

500

400

600

550

580

520

650

1. The ratio of investment
of UP to the state of AP in power sector is—
a) 10 : 13
b) 13 : 10
c) 10 : 21
d) 21 : 10
e) None of these
2. What is the ratio
between the investment in IT of AP and in other of UP ?
a) 65 : 63
b) 182 : 95
c) 63 : 65
d) 95 : 182
e) None of these
3. The total investment
in Road sector by these states is—
a) 800 cr
b) 720 cr
c) 760 cr
d) 700 cr
e) None of these
4. The FDI in cinema
sector in Delhi is what per cent less than that in Kerala in others ?
a) 40%
b) 80%
c) 50%
d) 60%
e) None of these
5. FDI in Maharashtra
in Telecom sector is what per cent of that in AP in IT sector ?
a) 42
b) 32
c) 62
d) 22
e) None of these
6. Walking at 4
km/hr, a person reaches his office 5 minutes late. If he walks at 5 km/hr, he
will be 4 minutes too early. Find the distance of his office from his
residence.
a) 1 km
b) 2 km
c) 3 km
d) 4 km
e) 5 km
7. A cow is sold
at a profit of 10%. Had it been sold for Rs 40 more, then profit would have
been 15%. Find the cost price of cow.
a) Rs.600
b) Rs.650
c) Rs.700
d) Rs.750
e) Rs.800
8. The list price
of a watch is Rs 160. After two successive discounts, it is sold for Rs 122.40.
If the first discount is 10%, what is the rate of second discount?
a) 12%
b) 15%
c) 17%
d) 22%
e) 25%
9. A person closes
his account in a bank by withdrawing Rs 110000. One year earlier, he had
withdrawn Rs 65000. Two years earlier, he had withdrawn Rs 125000. How much
money had he deposited in the bank at the time of opening the account three
years ago if the annual interest rate was 10% compounded annually?
a) Rs.150000
b) Rs.180000
c) Rs.200000
d) Rs.230000
e) Rs.250000
10. How many words
can be formed with the letters of the word ‘ORDINATE’ so that vowels occupy odd
places?
a) 432
b) 576
c) 892
d) 754
e) 962
Directions (11 – 15): What should come in place of the questions
mark (?) in the following questions?
11. (185)^{2 }+
(147)^{2}  (185)^{2} = ?
x 3
a) 7403
b) 6502
c) 7203
d) 8524
e) 4256
12. 5 1/7 +
213/14 × 35/55
a) 7.1254
b) 9.4331
c) 8.4351
d) 8.3151
e) none
13. 33/35 × 44/76 ×
38/1188 × 980/1496 × 1154 =? (Take 4 digits after the
decimal point)
a) 11.1819
b) 12.1519
c) 17.1219
d) 16.1819
e) 13.1619
14. (98746 + 96379
+ 99768 +74767) ÷ (763 + 998 + ? +2932) = 60
a) 1578
b) 1678
c) 1468
d) 1324
e) 2145
15. [(25)^{3/2}
+ (25)^{3/2}] is
a) 115.008
b) 135.128
c) 145.023
d) 125.008
e) none
Answers:
1)a 2)b 3)c
4)b 5)a 6)c
7)e 8)b 9)e
10)b 11)c 12)c
13)e 14)c 15)d
Solutions:
5. A) The required percentage = (13% of 550)/(28% of 650) × 100 =
42% approx.
6. C) Let the required distance = x km
Time taken at
4kmph = x/4 hrs = x/4 × 60 min = 15x min
Time taken at
5kmph = x/5 hrs = x/5 × 60 min = 12x min
Since the
difference between the two times taken is (5 + 4) = 9 minutes.
Therefore, 15x
 12x = 9 => 3x = 9 => x = 3
Hence the
required distance is 3 km
7. E) Let the cost price of cow be Rs 100.
Then, Selling
price of the cow at 10% profit = Rs 110
And selling
price at 15% profit = Rs115
Difference in
the selling prices = Rs (115 – 110) = Rs 5
Since, When
difference in selling price is Rs 5, cost price is Rs 100.
When difference
in selling price is Rs 40, cost price = 100/5 × 40 = Rs.800
8. B) List price = Rs 160,
The first
discount = 10% and the selling price = Rs 122.40
Let the rate of
second discount be x%.
Now, according
to the question,
122.40 = 160 × [(100
– 10)/100] × [(100 – x)/100]
=> 122.40 =
160 × 90/100 × (100 – x)/100
=> 100 – x =
12240 × 100/(160 × 90) = 85
Therefore x =
15%
Hence the
second discount is 15%
9. E) The person with draws Rs.110000
One year
earlier the person had Rs.(110000 × 10/11) = 100000
Two years
earlier the person had Rs.(100000 + 65000) × 10/11 = Rs.150000
At the time of opening
the account, the person had Rs.(150000 + 125000) × 10/11 = Rs.250000
10. B) There are 4 vowels and 4 consonants in the word
ORDINATE.
We have to
arrange 8 letters in a row such that vowels occupy odd places.
There are 4 odd
places 1, 3, 5 and 7.
Four vowels can
be arranged in these 4 odd places in 4P4 = 4! ways.
Remaining 4
even places viz 2, 4, 6, 8 are to be occupied by the 4 consonants.
This can be
done in 4P4 = 4! ways.
Hence the total
number of words in which vowels occupy odd places = 4! × 4! = 576
11. C) 34225 + 21609 – 34225 = ? x 3
=> 55834 –
34225 = ? x 3 => 21609/3 = ? => ? = 7203
12. C) 46/7 + 41/14 × 35/55 = ? => 46/7 +
1435/770 = ? => ? = 6495/770 => ? = 8.4351
13. E) ½ × 1/36 × 28/34 × 1154 = ?
=> 0.5 x
0.0277 x 0.8235 x 1154 =?
=> ? =
13.1619
14. C) 369660 ÷ (4693 + ?) = 60
=> 369660/60
= 4692 + ?
=> 6161 –
4693=?
=> ? =1468
15. D) [ (5^{2})^{3/2 } + (5^{2})^{3/2 } = ?
=> 5^{3}
+ 5^{3 }= ?
=> 125 + 1/125
= ?
=> ? =
125.008