RRB Quantitative Aptitude MCQ’s (Set – 1)
Dear Aspirants,
Welcome
to Mentor for Bank Exams. Railway exam will be conducted in the month of
April/May 2018 as per the official notification.Here we are giving the
important Quantitative Aptitude MCQ’s for upcoming RRB ALP/Technician and RRB
Group D in the exam oriented new pattern, these will help you to score good in Quant
section.
1. A money lender lent
out ₹ 20,000 in two parts, one at 10% interest and the other at 14% interest.
If the total annual income on the amount is ₹2500, the money lent at 10% is?
a) ₹8500
b) ₹12500
c) ₹10000
d) ₹7500
Answer: D)
Explanation: The
effective interest obtained = 100 x 2500 /20000 = 12.5%
By
the rule of allegations,
10 14
12.5
1.5 2.5
The
ratio of the two parts is 3:5.
So
money lent at 10% is 20000 x 3/8 = ₹7500
2. Evaluate
14*sin65*sec25+32*cos73*cosec17.
a) 46
b) 48
c) 52
d) 64
Answer: A)
Explanation: 14*sin65*sec25
+ 32*cos73*cosec17 = 14*sin (9025)*sec25+32*cos(9017)*cosec17
=>
14*sin65*sec25+32*cos73*cosec17 = 14*cos25*sec25+32*sin17*cosec17
=>
14*sin65*sec25+32*cos73*cosec17 = 14*( cos25/ cos25)+32(sin17/ sin17)
=>
14*sin65*sec25+32*cos73*cosec17 = 14+32=46
3. Delhi and
Chandigarh are 248 km apart. An express train leaves Delhi for Chandigarh at 6
pm and runs at an average speed of 60 km/hr. Another train leaves Chandigarh
for Delhi at the same time and runs at an average speed of 64 km/hr. Where will
the two trains meet?
a) 128 km
from Delhi
b) 130 km
from Chandigarh
c) 120 km
from Chandigarh
d) 120 km
from Delhi
Answer: D)
Explanation: Relative
speed of trains coming towards each other = sum of their speeds = 60 + 64 = 124
km/hr
Time
taken to reach the meeting point = Distance/Relative speed = 248/124 = 2 hours
Distance
from Delhi to the meeting point = Speed*Time = 60*2 = 120 km
Distance
from Chandigarh to the meeting point = Speed*Time = 64*2 = 128 km
4. A and B can do a
certain piece of work in 80/11 days. B worked for 7 days, then the remaining
work is completed by A in 10 days. Find in how many days B can complete the
whole work?
a) 7 days
b) 6 days
c) 10 days
d) 8 days
Answer: D)
Explaantion:
Let
A completes the work in x days.
B
completes the work in y days.
B
worked for 7 days then the remaining work is completed by A in 10 days.
(10/x)
+ (7/y) = 1  (1)
A
and B can do a certain piece of work in 80/11 days.
(80/11)*(1/x
+ 1/y) = 1
1/x
+ 1/y = 11/80
1/x
= 11/80  1/y
Putting
1/x in equation (1), we get
10(11/80
 1/y) + 7/y = 1
11/8
 10/y + 7/y = 1
3/y
= 11/8  1 = 3/8
y
= 8 days
5. The average age of
19 students in a class is 15 years. Out of these, the average age of 8 students
is 15 years and that of another 10 students is 14 years. The age of the 19th
student is ___.
a) 10 years
b) 9 years
c) 25 years
d) 15 years
Answer: C)
Explanation: Sum of the
ages of 19 students = 19 x 15 = 285
Sum
of the ages of 8 students = 15 x 8 = 120 and sum of ages of 10 students = 10 x
14 = 140
Age
of the 19^{th} student = 285  (120 + 140) = 25 years.
6. The area of a
circle is 660 m^2. The area of the square inscribed in this circle will be ___.
a) 140 m^2
b) 420 m^2
c) 240 m^2
d) 180 m^2
Answer: B)
Explanation: The area
of circle is πR^{2} = 660 and R^{2} = 7/22 x 660 = 210 m
Now,
R = 1/2 x (Diagonal) i.e., Diagonal = 2R
Therefore,
Area of the square = 1/2 x (Diagonal)^{2} = 1/2 x (2R)^{2} = 2R^{2}
= 2 x 210 = 420 m^{2}
7. If (3a + 5b)/(7a +
9b) = 1/2
What is the value of
(16a + 15b)/(13a + 17b) ?
a) 31/27
b) 31/30
c) 27/31
d) 4/5
Answer: B)
Explanation: (3a +
5b)/(7a + 9b) = 1/2
6a
+ 10b = 7a + 9b
b
= a
(16a
+ 15b)/(13a + 17b) = 31a/30a = 31/30
8. The difference
between a discount of 40% on Rs.500 and two successive discounts of 36% and 4%
on the same amount is:
a) Nil
b) Rs.2
c) Rs.7.20
d) Rs.1.93
Answer: C)
Explanation: 1^{st}
discount = Rs.(40% of 500)
=
Rs.(40/100 X 500) = Rs.200
2nd
discount = (36% of 500 + 4% of 64% of 500)
=
Rs. (36/100 X 500+ 4/100 X 64/100 X 500)
=Rs.192.80
Difference
= Rs. (200192.80) = Rs.7.20
9. The length of a
rectangular floor is twice its breadth. If 256rs is required to paint the floor
at the rate of 2rs per sq m, then what would be the length of the floor?
a) 16 m
b) 32 m
c) 64 m
d) 128 m
Answer: A)
Explanation: Rate of
painting = 2rs per sq m
Area
of rectangular floor = 256/2 = 128 sqm
Let,
breadth = x
Then,
length = 2x
Area
= l * b
128
= 2x * x
128
= 2x^{2}
x^{2}
= 64
x
= 8 m
Length
= 2x = 2 * 8 = 16m
10. Find tanq, if q is
acute and 7sin^2q + 3cos^2q = 4
a) 2/√3
b) 1/√3
c) 2/3
d) 1/3
Answer: B)
Explanation: 7sin^{2}q
+ 3cos^{2}q = 4
Dividing
by cos^{2}q, we get
=>
7tan^{2}q + 3 = 4sec^{2}q
=>
7tan^{2}q + 3 = 4(1+tan^{2}q)
=>
7tan^{2}q + 3 = 4 + 4tan^{2}q
=>
3tan^{2}q = 1
=>
tan^{2}q = 1/3
=>
tanq = 1/√3
11. A number is
divided such that 1/5th of the first part and 2/3th of the second part are
together equal to 1/2th of the original number. What is the ratio of the first
part of the number to its second part?
a) 5 : 2
b) 5 : 9
c) 2 : 3
d) 5 : 3
Answer: B)
Explanation: Let the number
be N and first part of the number be x, then the second part of the number will
be (Nx).
According
to the given question, x/5+2(Nx)/3=N/2
=>
3x + 10(Nx) = 15/2 N
=>
14x = 5N
Hence
ratio of first part to second part = x : (Nx) = x : (2.8x  x)
12. A, B, C have
monthly salary in the ratio 5:4:3. After getting a Diwali bonus of 10%, 25%,
and 50% respectively, their monthly salary will be in the ratio ?
a) 2:5:10
b) 11:10:9
c) 3:7:8
d) 4:5:6
Answer: B)
Explanation: After
getting a Diwali bonuses, each salary will be multiplied by the total increase.
i.e.
For 10% increase, the multiplication is by 1.1
For
25% increase, the multiplication is by 1.25
For
50% increase, the multiplication is by 1.5
=
5*1.1 : 4*1.25 : 3*1.5
=
11 : 10 : 9
13. The following
table shows ages of 4 different persons on 1st January 2017.
Person

Age
on 1^{st} January 2017 (In years)

Rajiv

24

Ram

14

Rama

15.5

Radha

12.5

If the age of Rima on
1st January 2016 was the average of ages of Rajiv, Ram, Rama and Radha on 1st
January 2017, then what will be the sum of the ages of Rima, Rajiv, Ram, Rama
and Radha together on 1st July 2018?
a) 90
years.
b) 92
years.
c) 91
years.
d) 93
years.
Answer: C)
Explanation: Age of Rima
on 1^{st} January 2016 = (24 + 14 + 15.5 +12.5)/4 = 66/4 =16.5 years.
Age
of Rima on 1^{st} January 2017 = 17.5 years.
On
1^{st} July 2018 age of each person will increase by 1.5 years,
Hence
required sum = (24 +14 +15.5 +12.5 +17.5) + (5 x 1.5) = 91 years
14. The following
table shows the ratio of number of boys to the number of girls in 5 classes.
Class

Ratio
of the number of boys to the number of girls

A

5:6

B

5:6

C

3:4

D

4: 5

E

2:3

If the number of boys
in class B is 9 more than the number of boys in class E and the number of girls
in class B is 6 more than the number of girls in class E and also the number of
girls in class D is equal to the number of boys in class B, then what is the
total number of boys in class D?
a) 26
b) 30
c) 28
d) 20
Answer: D)
Explanation: Let the
number of boys and the number of girls in class B are 5b and 6b respectively.
Let
the number of boys and the number of girls in class E are 2e and 3e respectively.
We
are given,
5b
 2e = 9.....................(1)
and
6b 3e =6
2be
= 2 .................... (2)
By
solving (1) and (2) we get b =5 and e = 8
Number
of boys in class B =25
Number
of girls in class D = Number of boys in class B = 25
In
class D
Number
of boys : Number of girls = 4 :5
Number
of boys : 25 = 4 :5
Hence
number of boys in class D =20.
15. The coordinates of
the vertices A and B are (6,0) and (0,8) respectively. What is the area of
square ABCD?
a) 81
b) 100
c) 225
d) 216
Answer: B)
Explanation: L(AB)=√
[(60)^{2}+(0+8)^{2}]=10.
∴ area of
the □ABCD=10^{2}=100 sq. units.