__Must Solve Profit and Loss Questions for SSC/RRB Exams__**1. A shopkeeper earns a profit equal to the selling price of 7 bags by selling 23 bags. What is the profit percentage?**

a) 43.75 percent

b) 30.4 percent

c) 60.8 percent

**2. A trader bought two cow for Rs. 19,500. He sold one at a loss of 20% and the other at a profit of 15%. If the selling price of each cow is the same, then their cost prices are respectively**

a) Rs. 10,000 and Rs. 9,500

b) Rs. 11,500 and Rs. 8,000

c) Rs. 12,000 and Rs. 7,500

d) Rs. 10,500 and Rs. 9,000

**3. Manish and Hari started a business investing amounts in the ratio of 2 : 3 respectively. If Manish had invested an additional amount of Rs. 10000, the ratio of Manish’s investment to Hari’s investment would have been 3 : 2. What was the amount invested by Manish initially?**

a) Rs. 8000

b) Rs. 12000

c) Rs. 18000

d) Rs. 4000

**4. The cost price of 8 pens is equal to selling price of 6 pens. What is the profit/loss percent?**

a) 33.33%

b) 25%

c) 30%

d) 50%

**5. A shopkeeper sells a radio on a discount of 8% on marked price and gains a profit of Rs. 25%. If marked price was Rs. 20,000 then, what was the cost price?**

a) Rs. 14,750

b) Rs. 14,552

c) Rs. 14,720

d) Rs. 14,850

**6. On allowing a discount of 20% on its marked price, the value of a watch is Rs.1600. If no discount is allowed, the shopkeeper gains 25%. What is the cost price of the watch?**

a) Rs.1600

b) Rs.1400

c) Rs.1296

d) Rs.1200

**7. A shopkeeper sells a watch at a loss of 12 1/2%. Had he sold the article for Rs. 63 more, he would have earned a profit of 10%. The cost price of the article is**

a) 280

b) 580

c) 370

d) 450

**8. The marked price of a table is Rs. 12,000. If it was sold for Rs. 10,500 after allowing a certain discount, then the rate of discount is**

a) 17.5%

b) 10%

c) 12.5%

d) 15%

**9. An oven when sold for Rs. 16,756, the profit earned is 18%. What is the cost price of the Oven?**

a) Rs. 14,200

b) Rs. 14,400

c) Rs. 15,200

d) Rs. 14,800

**10. ‘A’ sells an article to ‘B’ at a profit of 20% and ‘B’ sells it to ‘C’ at a profit of 25%. If ‘C’ pays Rs. 1,200, the cost price of the article originally (in Rs.) is**

a) 700

b) 600

c) 1,000

d) 800

**Solutions:**

**1. A)**Let the SP of 1 bag be ‘x’.

⇒ SP of 7 bags = 7x = profit

⇒ SP of 23 bags = 23x

Now, profit = SP – CP⇒ CP = SP – Profit = 23x – 7x = 16x

⇒ Profit % = ((SP – CP) /CP) × 100

⇒ ((23x – 16x) /16x) × 100

⇒ 43.75%

**2. B)**⇒ Let the cost of 1

^{st}cow be x then the cost of 2

^{nd}cow be y

⇒ Total cost of cow = 19,500 = x + y
------ 1

⇒ one sold at 20% loss and other at other at 15% profit

⇒ Selling at 20% loss (S. P

_{1}) = x - 20% of x
⇒ S. P

_{1 }= 0.8x
⇒ Selling at 15% profit (S. P

_{2}) = y + 15% of y
⇒ S. P

_{2 }= 1.15y
⇒ Selling Price is equal

⇒ 0.8x = 1.15y

⇒ x = (1.15/0.8) × y

⇒ x = 1.4375y

⇒ putting the value of x in equation 1 we have

⇒ 1.4375y + y = 19,500

⇒ 2.4375y = 19,500

⇒ y = 19,500/2.4375

∴ y = 8000

⇒ then x = 19,500 - 8000

∴ x = 11,500

**3. A)**Let the initial investment by Manish be Rs. 2x and by Hari be Rs. 3x

Now, if Manish had
invested R. 10000 more, his investment would be Rs. 2x + 10000

Now, according to the
question, (2x + 10000)/3x = 3/2

⇒ x = 20000/5 = 4000

∴ the amount invested by Manish initially = Rs. 2x = Rs. 8000

**4. A)**Let cost price of one pen = Rs. 1,

Cost price of 8 pens =
Rs. 8,

Cost price of 6 pens =
Rs. 6

Selling price of 6 pens =
cost price of 8 pens = Rs. 8

Profit gained = SP – CP =
Rs. (8 – 6) = Rs. 2

We know that, formula:

Profit percentage =
(Profit/CP) × 100%

∴ Profit percent = (2/6) × 100% = 33.33%

Hence, the required
profit percentage is 33.33%.

**Note:**it is not possible to find amount of profit/loss, because we neither know CP nor SP. They could take any values.

**Alternate Method (Short trick):**

CP of 8 pens = SP of 6
pens

CP of 1 pen × 8 = SP of 1
pen × 6

⇒ CP/SP = 6/8 hence, there is a profit.

Now, let CP = Rs. 6 then
SP = Rs. 8

Profit = SP – CP = Rs. (8
– 6) = Rs. 2

∴ Profit percent = (2/6) × 100% = 33.33%

**5. C)**Given that,

Discount = 8% of marked
price

= Rs. {20000 × 8/100} =
Rs. 1600

∴ Selling price = Marked price – discount = Rs. (20,000 – 1600) = Rs. 18,400

Now, according to the
question, a profit of 25% is gained on selling the radio.

We know that, formula:

Profit percentage =
(Profit/CP) × 100%

∴ Required CP = Rs. {18400 × 100/125} = Rs. 14,720.

Hence, the cost price of
the radio was Rs. 14,720.

**6. A)**Let the marked price of the watch be M and the cost price be C.

On allowing a discount of
20%, we have the selling price to be Rs.1600.

⇒1600 = M(1 − 20/100) = M × 4/5 = 4/5M ⇒ M=2000

It is given that if the
watch is sold at the marked price, the profit percentage would be 25%,

⇒25/100 = (2000 − C)/C
⇒ 1/4 = (2000 – C)/C

⇒ C = 8000 – 4C ⇒ 5C = 8000 ⇒ C = 1600

**7. A)**Let the cost price of the article be C, and the selling price be S.

Loss% = (C – S)/C =>
12.5/100 = (C – S)/C ⇒ C = 8C – 8S ⇒ 8S =
7C ⇒ S = 7C/8

Given, had he sold
Rs.63 more, he would have earned a profit of 10%.

10/100 = (S + 63) – C/C ⇒ C = 10S + 630 – 10 ⇒ 11C – 10S = 630

⇒ 11C – 10 × 7/8C = 630 ⇒ 11C – 35/4C = 630 ⇒ (44C – 35C)/4 = 630 ⇒ 9C/4 = 630 ⇒ C = 280

**8. C)**The marked price of the table is Rs. 12,000.

It is sold for Rs. 10,500
after allowing a certain discount.

∴ Discount offered: = marked price – selling price = Rs. 12000
– Rs. 10500 = Rs. 1500

Discount offered = Rs.
1500 when marked price of the table is Rs. 12,000.

Then the rate of discount
is:

= 1500/12000 * 100 =
12.5%

**9. A)**Let the original cost of the oven be x.

An oven when sold for Rs.
16,756, the profit earned is 18%.

SP = CP + profit

⇒ x + (18/100 * x) = 16756
⇒ 118x / 100 = 16756 ⇒ x = (16756 × 100)/118 ⇒ x = Rs. 14200

**10. D)**Let the cost price of the article be ‘x’.

A sells it to B at a
profit of 20%.

We know that,

Selling price = Cost
price + Profit

Profit = 20x/100

⇒ Selling price of A = x + 0.2x = 1.2x

Selling price of A = Cost
price of B

B had a profit of 25%.

B’s profit = 25/100 *
1.2x = 0.3x

Selling price of B = 1.2x
+ 0.3x = 1.5x

As per problem,

⇒ 1.5x = 1200 ⇒ x = 800.

Original cost price = Rs.
800.