Quantitative Aptitude Practice Questions for IBPS Clerk – Set 23

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Quantitative Aptitude Practice Questions for IBPS Clerk – Set 23
1. P can finish a work in 18 days. Q can finish the same work in 15 days. Q started the work, worked for 10 days and left the job. How many days does P alone need to finish the remaining work?
a) 13
b) 8
c) 6
d) 5
e) 7
2. 40 pens and 80 pencils were purchased for Rs. 520. If the average price of a pencil was Rs. 2.00, find the average price of a pen.
a) Rs. 10
b) Rs. 11
c) Rs. 9
d) Cannot be determined
e) None of the above
3. The principal is 25 times its simple interest. What are the rate of interest and time if they are equal?
a) 2 years, 2%
b) 3 years, 3%
c) 4 years, 4%
d) 10 years, 10%
e) None of these
4. P sold a pendant to Q at a loss of 20%. Q sold it to R at a loss of 30%. At what price should R sell it to S to earn a profit of Rs. 40?
a) Rs. 144
b) Rs. 156
c) Rs. 80
d) Rs. 120
e) Cannot be determined
5. Ramesh mixes 15 kg of sugar purchased at the rate of Rs. 10 per kg with 25 kg of sugar purchased at the rate of Rs. 12 per kg. At what rate per kg, should Ramesh sell the mixture to get a profit of Rs. 3 per kg?
a) Rs. 14.00
b) Rs. 12.25
c) Rs. 14.25
d) Rs. 12.50
e) None of these
6. By how much the fourth proportional to 26, 143 and 68 will be more than third proportional to 49 and 63?
a) 198
b) 263
c) 293
d) 374
e) 455
7. A 150 metre-long train passes a bridge at 72 km per hour in 27 seconds. The length of the bridge is
a) 150 m
b) 410 m
c) 390 m
d) 540 m
e) 350 m
8. Gibbs invested an amount of Rs. 4000 in compound interest for 3 years at 10% per annum rate of interest. How much money should he invest in simple interest so as to earn same amount of interest at same rate in 4 years?
a) Rs. 3000
b) Rs. 3310
c) Rs. 3620
d) Rs. 4420
e) Rs. 3760
9. A boat takes 30 hours for travelling downstream from point A to point B and coming back to point C midway between A and B. If the velocity of the stream is 5 km/hr and the speed of the boat in still water is 10 km/hr, what is the distance between A and B?
a) 146km
b) 150km
c) 180km
d) 190km
e) None
10. Weights of two friends P and Q are in the ratio 4:5. If P’s weight is increased by 10% and total weight of P and Q become 82.8 kg, with an increases of 15%. By what percent did the weight of Q has to be increased?
a) 19%
b) 22%
c) 17.5%
d) 12.5%
e) None
Directions (11 – 15): What approximate value should come in place of question mark (?) in the following questions?
11. (5 / 6) × [(2 / 9) ÷ (4 / 9)] ÷ (6 / 7) = ?
a) 0.44
b) 0.32
c) 0.49
d) 1.6
e) 0.35
12. 15% of 62.5 + 10% of 4.80 = ?
a) 14.18
b) 15.20
c) 10
d) 16
e) 18
13. 543.28 ÷ 55 = ?
a) 4
b) 8
c) 10
d) 12
e) 9
14. [(3 / 0.8) × (11 / 0.2)] ÷ [(28 / 3) × (21 / 5)] = ?
a) 3
b) 5
c) 7
d) 9
e) 13
15. (1.1)^2 + (3.2)^2 + (3.0)^2 = ?
a) 20
b) 22
c) 24
d) 25
e) 27


Solutions:
1. C) P can finish a work in 18 days.
Work done by P in 1 day = 1/18
Q can finish a work in 15 days.
Work done by Q in 1 day = 1/15
Q worked for 10 days.
Work done by Q in 10 days = 10/15 = 2/3
Remaining work = 1 2/3 = 1/3
Number of days in which P can finish the remaining work = (1/3)/(1/18) = 6 days
2. C) We know,
Average of quantities = sum of all quantities/no. of quantities
40 pens and 80 pencils were purchased for Rs. 520.
The average price of a pencil was Rs. 2.00. So, the total price of 80 pencils = Rs. 80 × 2 = Rs. 160
The total price of 40 pens = Rs. (520 – 160) = Rs. 360
The average price of a pen = Rs. 360/40 = Rs. 9
3. A) Let the simple interest be ‘a’.
principal is 25 times simple interest, principal = 25a
Let the time be ‘t’ years. Since the time and the rate of interest are equal,
Rate of interest = t%
We know that,
Simple Interest = (P × R × T)/100
Where, P = principal Amount, R = % Rate of interest, T = time period in years
Here, P = 25a; R = t; T = t; SI = a
a = (25a×t×t)/100
t2 = 4
t = 2 years
Rate of interest = t = 2%
4. E) R earns a profit of Rs. 40. To know the price at which R sold to S, we must know the price at which R bought from Q. But we know only the loss percentages at which pendant was sold from P to Q to R. Actual value at which Q sold pendant to R cannot be uniquely found with this data.
5. C) C.P. of the 15 kg sugar @ Rs. 10 per kg = 15 × 10 = Rs. 150
C.P of the 25 kg sugar @ Rs. 12 per kg = 25 × 12 = Rs. 300
Average cost price of 1 kg mixture = (150+300)/(15+25) = 450/40 = 11.25
Ramesh sells the mixture to get a profit of Rs. 3 per kg
Selling price per kg = 11.25 + 3 = 14.25 per kg
6. C) Let Fourth proportional to 26, 143 and 68 be P.
26/143 = 68/P
P = 374
Let Third proportional to 49 and 63 be Q.
49/63 = 63/Q
Q = 81
Difference = 374 81 = 293
7. C) Speed of the train = 72km/hr
Converting the speed of train into m/sec = 72 × 5/18 = 20m/sec
Time taken to cross the bridge = 27 sec
Distance covered by train to cross the bridge = 27 × 20 = 540 m
Length of the bridge = Distance covered by the train – length of the train
Length of the bridge = 540 150
Length of the bridge = 390 m
Hence, the length of the bridge is 390 m
8. B) Compound Interest = Principal × [(1+R/100)^T−1]
Interest earned = 4000 × ((1 + (10/100))3 -1) = 4000 × 0.331 = 1324
To earn same amount of simple interest at 10% per annum rate of interest in 4 years,
Simple interest = (Principal × Rate × Time)/100
1324 = (Principal × 10 × 4)/100
Principal = 132400/40 = 3310
Rs. 3310 should be invested in simple interest.
9. C) Downstream speed= 10+5 = 15
Upstream speed = 10-5 = 5
Now total time is 30 hours
If distance between A and B is d, then distance BC = d/2
Now distance/speed = time, so
d/15 + (d/2)/5= 30
Solve, d = 180 km.
10. A)
10……………..x
……….15
x-15 : 15-10
Now, given ratio of P and Q’s weight = 4:5
Hence, (x-15)/(15-10) = 4/5
x = 19%.
11. C) ? = (5 / 6) × [(2 / 9) ÷ (4 / 9)] ÷ (6 / 7)
= (5 / 6) × [ 1 / 2 ] × (7 / 6) = (35 / 72)
= 0.486 ≈ 0.49
12. C) ? = [(15 × 62.5) / 100] + [(10 × 4.80) / 100]
= 9.375 + 0.48 = 9.855 ≈ 10
13. C) ? = 543.28 / 55 = 9.8778 = 10
14. B) ?= (33 / 0.16) × [5 / (28 × 7)] = (165 / 31.36) = 5.26 ≈ 5
15. A) ? = 1.21 + 10.24 + 9 = 20.45 ≈ 20