Quantitative Aptitude Practice Questions for IBPS PO Mains –
Set 4
Directions
(1 – 5): Study the following Line  chart carefully to answer these
questions
1. D and E
started the task together and E left after some time. D completed the remaining
work in 2 hour. After how many hours from the start did E leave?
a) 1.25
hour
b) 1.5 hour
c) 2 hour
d) 2.25
hour
e) 2.5 hour
2. Approximately
how long will it take for A, B, F and G together to complete the task?
a) 1.6 hour
b) 1.9 hour
c) 2.3 hour
d) 2.7 hour
e) 3.1 hour
3. D, F and
G worked on the task for one hour and then D and G left. If F complete the
remaining work, then how many more hours did F take to finish the remaining
work?
a) 10.4
hour
b) 11.8
hour
c) 12.2
hour
d) 14.4
hour
e) 15.2
hour
4. If C
leaves 2 hours after A and C started the task, then how many more hour will A
take to complete it?
a) 1.8 hour
b) 2.1 hour
c) 2.8 hour
d) 3.4 hour
e) 4.2 hour
5. In how
much time can A and C together complete the task?
a) 2.5 hour
b) 3 hour
c) 3.5 hour
d) 3.75
hour
e) 4 hour
Directions
(6 – 10): Study the data given below and answer the following questions.
The pie charts shown
below shows the distance covered by a boat moving upstream and downstream in different
days of a week.
And the table shows
the speed of stream in km/hr. in different days of a week.
Day

Speed
of stream (kmph)

Monday

5

Tuesday

2

Wednesday

6

Thursday

–

Friday

1

Saturday

–

Sunday

3

6. If the
time taken by boat to travel upstream on Wednesday is 6/7 times than the time
taken to travel downstream on Monday and the speed of boat in still water on
Monday is 15 kmph then find the speed of boat in
still water on Wednesday? ( speed of boat in still water is different for different days) (2 mark)
a) 52 kmph
b) 62 kmph
c) 42 kmph
d) 48 kmph
e) None of
these
7. If the
time taken by boat to travel upstream on Monday is 27 1/5hrs. more than the
time taken by it to travel downstream on the same day, then find the speed of boat in still water on Monday ? (speed of boat in
still water is same in upstream as in downstream)
a) 25kmph
b) 18kmph
c) 20kmph
d) 15kmph
e) None of
these
8. If the
speed of boat in still water on Saturday was 27 km/hr and the speed of boat in
still water on Wednesday was 66 2/3% more than that of Saturday and time taken
to travel upstream on Wednesday is 16/13 times than time taken by it to travel
downstream on Saturday, then find the speed of stream (in
kmph) on Saturday? (2 mark)
a) 2
b) 4
c) 9
d) 8
e) None of
these
9. The
speed of boat in still water on Saturday was 21 km/hr. and that on Sunday was
more than that on Saturday, if the time taken by boat to travel upstream on
Saturday is times than time taken to travel downstream on Sunday, then find the time taken by the boat to cover a distance of 125 km
upstream on Saturday?
a) 6 hrs.
45 min.
b) 2 hrs.
45 min.
c) 4 hrs.
30 min.
d) 6 hrs.
15 min.
e) None of
these
10. If the
time taken by boat to travel upstream on Friday is 30 hours more than the time
taken by it to travel downstream on Wednesday and the speed of boat in still
water on Friday is 17 kmph, then find the upstream speed of
boat on Wednesday? (speed of boat in stiil water is different on different days) (2 mark)
a) 27 kmph
b) 22 kmph
c) 20 kmph
d) 25 kmph
e) None of
these
Directions
(11 – 13): The below question is asked followed by three statements. You have
to study the question and all the three statements given and decide whether any
information provided in the statement(s) are redundant and can be dispensed
with while answering the question?
11. How
much time will a boat take to cross the river against the stream of the river?
(I) In still
water the speed of the boat is 15 km/hr
(II) The width
of the river is 8 km
(III) The speed
of the stream is 2km/hr.
a) Only
I
b) Only
II
c) Only III
d) None of
these
e) Insufficient
data
12. What is
the amount saved by Sahil per month from his salary?
(I) Sahil
spends 25% of his salary on food, 35% on medicine and education and Rs 2400 on
entertainment.
(II) Sahil
spends Rs.4000 per month on food.
(III) Sahil
spends Rs.5600 per month on medicine and education.
a) Only I
b) Only
II
c) Both II
and III
d) Either
II or III
e) None of
these
13. What
will be the sum of the ages of father and the son after five years?
(I) Father’s
present age is twice son’s present age
(II) After ten
years the ratio of father’s age to the son’s age will become 12 : 7
(III) Five years
ago the difference between the father’s age and son’s age was equal to the
son’s present age.
a) Only I
or II
b) Only II
or III
c) Only I
or III
d) Only III
e) Only I
or II or III
Directions
(14 – 15): Alcohol and water are mixed in a vessel A in the proportion 5
: 2, and in vessel B in the proportion 8 : 5
14. In
vessel A the quantities of mixture is 56 liter, find the quantity of Alcohol in
vessel
a) 40 litre
b) 45 litre
c) 42 litre
d) 35 litre
e) 44 litre
15. In what
proportion should quantities be taken from the two vessels so as to form a
mixture in which Alcohol and water will be in the proportion of 9 : 4?
a) 7 : 2
b) 9 : 2
c) 5 : 6
d) 4 : 3
e) 8 : 3
Solutions:
1. D) Let the time for which E worked be
x hours
One
 hour work of E = 1/15
Work
done by E = (x ) × 1/15
One
 hour work of D = 1/5
Time
for which D worked = (x + 2) hours
Work
done by D = (x + 2) × 1/5
Total
work done by D and E = 1
x/15
+ (x + 2)/5 = 14x + 6 = 15
x
= 9/4 = 2.25 hour
2. D) A’s one 
hour work = 1/6
B’s
one  hour work = 1/12
F’s
one  hour work = 1/18
G’s
one  hour work = 1/15
If
all of them work together, their one  hour work = 1/6 + 1/12 + 1/18 + 1/15 =
67/180
Total
time taken = 182/67 = 2.69 hour
3. C) One  hour
work of D = 1/5
F’s
one  hour work = 1/18
G’s
one  hour work = 1/15
Total
work done in one hour = 1/5 + 1/18 + 1/15 = 29/90
Work
left = 1 – 29/90 = 61/90
Time
taken by F to complete the left work = (61/90) / (1/18) = 61/5 = 12.2
hour
4. C) A’s one 
hour work = 1/6
C
can do work in 10 hours
C’s
one  hour work = 1/10
A
and C ‘s one  hour work if they work together = (1/6 + 1 /10) = 16/60
Total
work done in 2 hours = 16/30
Work
left = 1 – 16/30 = 14/30
Time
taken by A to complete the rest of work = (14/30) / (1/6) = 14/5 = 2.8 hour
5. D) A can do
work in 6 hours
A’s
one  hour work = 1/6
C
can do work in 10 hours
C’s
one  hour work = 1/10
A
and C ‘s one  hour work if they work together = (1/6 + 1 /10) = 16/60
Time
taken by them together to complete whole work = 60/16 = 3.75 hours
6. E) According
to the question,
(12
× 48)/(x – 6) = [(14 × 24)/(15 + 5)] × 6/7 => x – 6 = 40 => x = 46kmph
7. A) According
to the question,
(16
× 48)/(x – 5) = (14 × 24)/(x + 5) + 27 1/5
By
option verification of we put x = 25
Then
LHS = RHS
8. C) Given Speed
of boat in still water on Saturday = 27kmph
and
Speed of Boat in still water on Wednesday = 27 + 18 = 45kmph
Now,
(12 × 48)/(45 – 6) = (18 × 24)/(27 + x) × 16/13
On
solving the above equation we get, x = 9kmph
9. D) Speed of
boat in still water on Saturday = 21kmph
Speed
of boat in still water on Sunday = 21 + 6 = 27kmph
Then,
ATQ,
(10
× 48)/(21 – x) = 5/2 × [(12 × 24)/(27 + 3)]
=>
21 – x = 20 => x = 1kmph
Therefore
required time = 125/(21 – 1) = 125/20 = 6hrs 15min
10. E) ATQ,
(14
× 48)/(17 – 1) = 30 + [(11 × 24)/(x + 6)]
=>
x + 6 = 22 => x = 16km
Upstream
speed on Wednesday = 16 – 6 = 10kmph
11. D) We know
that,
Speed
= Distance/Time
While
moving upstream,
Speed
= Speed of the boat – Speed of the water current
∴ Speed = 15
– 2 = 13 km/hr
Distance
= 8 km
∴ Time = Distance/Speed
= 8/13 = 0.62 hours
∵ The speed
of the boat is given by statement (1), speed of the water current by (3) and
the distance by (2), none of the three statements is redundant.
12. D) Given, the
percentage of salary, Sahil spends on food is 25% and on medicine and education
is 35% and Rs 2400 on entertainment in statement(1) and the actual amount spent
on food in Rs in statement (2) and the actual amount spent on medicine and
education in statement (3).
Based
on above statement, either statement (2) or statement (3) can be dispensed.
13. C) Let the
present ages of father and son be ‘x’ and ‘y’
Considering
statements (1) and (2)
⇒ x = 2y
∴ x – 2y = 0    (1)
Also,
(x + 10)/(y + 10) = 12/7
∴ 7x + 70 =
12y + 120
∴ 7x – 12y = 50    (2)
On
solving (1) and (2),
⇒ x = 50 and
y = 25
Considering
statements (2) and (3)
(x
+ 10)/(y + 10) = 12/7
∴ 7x – 12y = 50    (3)
And,
(x  5) – (y  5) = y
∴ x – 5  y + 5 = y
∴ x – 2y = 0    (4)
On
solving (3) and (4),
⇒ x = 50 and
y = 25
Considering
statements (1) and (3)
⇒ x = 2y
∴ x – 2y = 0    (5)
Also,
(x  5) – (y  5) = y
∴ x – 2y = 0    (6)
(5)
and (6) are the same
⇒ the above
statements cannot be solved together.
∴ either of
statements (1) or (3) can be dispensed.
14. A) Let the
quantity of alcohol in vessel A = 5x
⇒ 5x + 2x =
56
⇒ x = 8
∴ quantity
of alcohol in vessel A = 8 × 5 = 40
litre
15. A) By the rule
of allegation
Alcohol
in A Alcohol in B
5/7 8/13
9/13
1/13 2/91
Therefore
required ratio = 1/13 : 2/91 = 7 : 2