# Quantitative Aptitude Practice Questions for IBPS PO Mains – Set 4

Quantitative Aptitude Practice Questions for IBPS PO Mains – Set 4
Directions (1 – 5): Study the following Line - chart carefully to answer these questions

1. D and E started the task together and E left after some time. D completed the remaining work in 2 hour. After how many hours from the start did E leave?
a) 1.25 hour
b) 1.5 hour
c) 2 hour
d) 2.25 hour
e) 2.5 hour
2. Approximately how long will it take for A, B, F and G together to complete the task?
a) 1.6 hour
b) 1.9 hour
c) 2.3 hour
d) 2.7 hour
e) 3.1 hour
3. D, F and G worked on the task for one hour and then D and G left. If F complete the remaining work, then how many more hours did F take to finish the remaining work?
a) 10.4 hour
b) 11.8 hour
c) 12.2 hour
d) 14.4 hour
e) 15.2 hour
4. If C leaves 2 hours after A and C started the task, then how many more hour will A take to complete it?
a) 1.8 hour
b) 2.1 hour
c) 2.8 hour
d) 3.4 hour
e) 4.2 hour
5. In how much time can A and C together complete the task?
a) 2.5 hour
b) 3 hour
c) 3.5 hour
d) 3.75 hour
e) 4 hour
Directions (6 – 10): Study the data given below and answer the following questions.
The pie charts shown below shows the distance covered by a boat moving upstream and downstream in different days of a week.
And the table shows the speed of stream in km/hr. in different days of a week.

 Day Speed of stream (kmph) Monday 5 Tuesday 2 Wednesday 6 Thursday – Friday 1 Saturday – Sunday 3
6. If the time taken by boat to travel upstream on Wednesday is 6/7 times than the time taken to travel downstream on Monday and the speed of boat in still water on Monday is 15 kmph then find the speed of boat in still water on Wednesday? ( speed of boat in still water is different for different days) (2 mark)
a) 52 kmph
b) 62 kmph
c) 42 kmph
d) 48 kmph
e) None of these
7. If the time taken by boat to travel upstream on Monday is 27 1/5hrs. more than the time taken by it to travel downstream on the same day, then find the speed of boat in still water on Monday ? (speed of boat in still water is same in upstream as in downstream)
a) 25kmph
b) 18kmph
c) 20kmph
d) 15kmph
e) None of these
8. If the speed of boat in still water on Saturday was 27 km/hr and the speed of boat in still water on Wednesday was 66 2/3% more than that of Saturday and time taken to travel upstream on Wednesday is 16/13 times than time taken by it to travel downstream on Saturday, then find the speed of stream (in kmph) on Saturday? (2 mark)
a) 2
b) 4
c) 9
d) 8
e) None of these
9. The speed of boat in still water on Saturday was 21 km/hr. and that on Sunday was more than that on Saturday, if the time taken by boat to travel upstream on Saturday is times than time taken to travel downstream on Sunday, then find the time taken by the boat to cover a distance of 125 km upstream on Saturday?
a) 6 hrs. 45 min.
b) 2 hrs. 45 min.
c) 4 hrs. 30 min.
d) 6 hrs. 15 min.
e) None of these
10. If the time taken by boat to travel upstream on Friday is 30 hours more than the time taken by it to travel downstream on Wednesday and the speed of boat in still water on Friday is 17 kmph, then find the upstream speed of boat on Wednesday? (speed of boat in stiil water is different on different days) (2 mark)
a) 27 kmph
b) 22 kmph
c) 20 kmph
d) 25 kmph
e) None of these
Directions (11 – 13): The below question is asked followed by three statements. You have to study the question and all the three statements given and decide whether any information provided in the statement(s) are redundant and can be dispensed with while answering the question?
11. How much time will a boat take to cross the river against the stream of the river?
(I) In still water the speed of the boat is 15 km/hr
(II) The width of the river is 8 km
(III) The speed of the stream is 2km/hr.
a) Only I
b) Only II
c) Only III
d) None of these
e) Insufficient data
12. What is the amount saved by Sahil per month from his salary?
(I) Sahil spends 25% of his salary on food, 35% on medicine and education and Rs 2400 on entertainment.
(II) Sahil spends Rs.4000 per month on food.
(III) Sahil spends Rs.5600 per month on medicine and education.
a) Only I
b) Only II
c) Both II and III
d) Either II or III
e) None of these
13. What will be the sum of the ages of father and the son after five years?
(I) Father’s present age is twice son’s present age
(II) After ten years the ratio of father’s age to the son’s age will become 12 : 7
(III) Five years ago the difference between the father’s age and son’s age was equal to the son’s present age.
a) Only I or II
b) Only II or III
c) Only I or III
d) Only III
e) Only I or II or III
Directions (14 – 15): Alcohol and water are mixed in a vessel A in the proportion 5 : 2, and in vessel B in the proportion 8 : 5
14. In vessel A the quantities of mixture is 56 liter, find the quantity of Alcohol in vessel
a) 40 litre
b) 45 litre
c) 42 litre
d) 35 litre
e) 44 litre
15. In what proportion should quantities be taken from the two vessels so as to form a mixture in which Alcohol and water will be in the proportion of 9 : 4?
a) 7 : 2
b) 9 : 2
c) 5 : 6
d) 4 : 3
e) 8 : 3​

Solutions:
1. D) Let the time for which E worked be x hours
One - hour work of E = 1/15
Work done by E = (x ) × 1/15
One - hour work of D = 1/5
Time for which D worked = (x + 2) hours
Work done by D = (x + 2) × 1/5
Total work done by D and E = 1
x/15 + (x + 2)/5 = 14x + 6 = 15
x = 9/4 = 2.25 hour
2. D) A’s one - hour work = 1/6
B’s one - hour work = 1/12
F’s one - hour work = 1/18
G’s one - hour work = 1/15
If all of them work together, their one - hour work = 1/6 + 1/12 + 1/18 + 1/15 = 67/180
Total time taken = 182/67 = 2.69 hour
3. C) One - hour work of D = 1/5
F’s one - hour work = 1/18
G’s one - hour work = 1/15
Total work done in one hour = 1/5 + 1/18 + 1/15 = 29/90
Work left = 1 – 29/90 = 61/90
Time taken by F to complete the left work = (61/90) / (1/18) = 61/5 = 12.2 hour
4. C) A’s one - hour work = 1/6
C can do work in 10 hours
C’s one - hour work = 1/10
A and C ‘s one - hour work if they work together = (1/6 + 1 /10) = 16/60
Total work done in 2 hours = 16/30
Work left = 1 – 16/30 = 14/30
Time taken by A to complete the rest of work = (14/30) / (1/6) = 14/5 = 2.8 hour
5. D) A can do work in 6 hours
A’s one - hour work = 1/6
C can do work in 10 hours
C’s one - hour work = 1/10
A and C ‘s one - hour work if they work together = (1/6 + 1 /10) = 16/60
Time taken by them together to complete whole work = 60/16 = 3.75 hours
6. E) According to the question,
(12 × 48)/(x – 6) = [(14 × 24)/(15 + 5)] × 6/7 => x – 6 = 40 => x = 46kmph
7. A) According to the question,
(16 × 48)/(x – 5) = (14 × 24)/(x + 5) + 27 1/5
By option verification of we put x = 25
Then LHS = RHS
8. C) Given Speed of boat in still water on Saturday = 27kmph
and Speed of Boat in still water on Wednesday = 27 + 18 = 45kmph
Now, (12 × 48)/(45 – 6) = (18 × 24)/(27 + x) × 16/13
On solving the above equation we get, x = 9kmph
9. D) Speed of boat in still water on Saturday = 21kmph
Speed of boat in still water on Sunday = 21 + 6 = 27kmph
Then, ATQ,
(10 × 48)/(21 – x) = 5/2 × [(12 × 24)/(27 + 3)]
=> 21 – x = 20 => x = 1kmph
Therefore required time = 125/(21 – 1) = 125/20 = 6hrs 15min
10. E) ATQ,
(14 × 48)/(17 – 1) = 30 + [(11 × 24)/(x + 6)]
=> x + 6 = 22 => x = 16km
Upstream speed on Wednesday = 16 – 6 = 10kmph
11. D) We know that,
Speed = Distance/Time
While moving upstream,
Speed = Speed of the boat – Speed of the water current
Speed = 15 2 = 13 km/hr
Distance = 8 km
Time = Distance/Speed = 8/13 = 0.62 hours
The speed of the boat is given by statement (1), speed of the water current by (3) and the distance by (2), none of the three statements is redundant.
12. D) Given, the percentage of salary, Sahil spends on food is 25% and on medicine and education is 35% and Rs 2400 on entertainment in statement(1) and the actual amount spent on food in Rs in statement (2) and the actual amount spent on medicine and education in statement (3).
Based on above statement, either statement (2) or statement (3) can be dispensed.
13. C) Let the present ages of father and son be ‘x’ and ‘y’
Considering statements (1) and (2)
x = 2y
x 2y = 0       - - - (1)
Also, (x + 10)/(y + 10) = 12/7
7x + 70 = 12y + 120
7x 12y = 50       - - - (2)
On solving (1) and (2),
x = 50 and y = 25
Considering statements (2) and (3)
(x + 10)/(y + 10) = 12/7
7x 12y = 50        - - - (3)
And, (x - 5) – (y - 5) = y
x 5 - y + 5 = y
x 2y = 0         - - - (4)
On solving (3) and (4),
x = 50 and y = 25
Considering statements (1) and (3)
x = 2y
x 2y = 0        - - - (5)
Also, (x - 5) – (y - 5) = y
x 2y = 0         - - - (6)
(5) and (6) are the same
the above statements cannot be solved together.
either of statements (1) or (3) can be dispensed.
14. A) Let the quantity of alcohol in vessel A = 5x
5x + 2x = 56
x = 8
quantity of alcohol in vessel A = 8 × 5 = 40 litre
15. A) By the rule of allegation
Alcohol in A              Alcohol in B
5/7                             8/13
9/13
1/13                           2/91
Therefore required ratio = 1/13 : 2/91 = 7 : 2