Quantitative Aptitude Practice Questions for IBPS Clerk – Set 13

Mentor for Bank Exams
Quantitative Aptitude Practice Questions for IBPS Clerk – Set 13
Directions (1 – 5): What should come in place of question mark (?) in the following number series?
1. 180         181         208         333         676         ?
a) 1676
b) 1019
c) 757
d) 1405
e) 1188
2. 10, 12, 28, 90, 368, 1840, 11112
a) 1840
b) 368
c) 90
d) 28
e) None of these
3. 668   656   632   584  ?   296
a) 392
b) 438
c) 488
d) 536
e) None of these
4. 6417     5704      4991     4278      3565          2852      ?
a) 2408
b) 2426
c) 7310
d) 7130
e) 2139
5. 3       3       12     108   ?       43200
a) 2700
b) 1728
c) 972
d) 432
e) None of these
Directions (6 – 10): In the following questions two equations numbered I and II are given. You have to solve both the equations and –
a) If x > y
b) If x ≥ y
c) If x < y
d) If x ≤ y
e) If x = y or the relationship can not be established

Directions (11 – 15): What approximate value will come in place of question mark (?) in the following question? (Note: – You are not expected to calculate the exact value)




Solutions:
1. D) The pattern of the given number series is:
180,
180 + 13 = 181,
181 + 33 = 208,
208 + 53 = 333,
333 + 73 = 676,
676 + 93 = 1405
Hence, the required term of the given number series is 1405
2. A) The pattern of the given number series is as:
10,         
10 × 1 + 2 = 12,
12 × 2 + 4 = 24 + 4 = 28,
28 × 3 + 6 = 84 + 6 = 90,
 90 × 4 + 8 = 360 + 8 = 368,
 368 × 5 + 10 = 1840 + 10 = 1850, (instead of 1840)
 1850 × 6 + 12 = 11100 + 12 = 11112,
Hence, the wrong term of the given number series is 1840. The correct term is 1850.
3. C) The rule followed is
The difference between the digits has started from 12 and every time changes to twice its value and so on
i.e.
668 - 656 = 12
656 - 632 = 12 × 2 = 24
632 - 584 = 24 × 2 = 48
584 - ? = 48 × 2 =96
? - 296 = 96 × 2 = 192
Solving for ? by both the equations
? = 488
4. E) We have each term of this series as follows:
6417 = 713 × 9
5704 = 713 × 8
4991 = 713 × 7
4278 = 713 × 6
3565 = 713 × 5
2852 = 713 × 4
? = 713 × 3
? = 2139
5. B) We have each term of this series as follows:
3 = 3 × 12
12 = 3 × 22
108 = 12 × 32
? = 108 × 42
? = 108 × 16
? = 1728
6. C) x = -70; y = 122. Therefore x < y
7. A) x = 3, 4 and y = -4, -8. Therefore x > y
8. B) x = ±3 and y = -3. Therefore x ≥ y
9. A) x = -32, -6 and y = 13, 5. Therefore x < y
10. E) x = ±6; y = ±4. Relationship cannot be determined
11. A)   12. C)   13. D)   14. B)   15. E)