Reasoning Ability Practice Questions for IBPS Clerk – Set 8

Mentor for Bank Exams
Reasoning Ability Practice Questions for IBPS Clerk – Set 8
Directions (1 – 5): Study the following information carefully and answer the questions given beside:
In a certain code language,
‘Wind is Another feel’ is written as ‘15N* 23J@ 18I# 1N#’
‘Tomorrow Ride like the’ is written as ‘12I# 4M$ 4V^ 6L#’
‘Think less little Day’ is written as ’20O$ 4P% 12P# 12I&’
‘Enjoy the things more’ is written as ‘11I# 19O% 4T& 4M$’
1. What is the code for the word ‘Hindi Medium’?
a) 17P% 12M&
b) 16I% 18V$
c) 16I%  11M&
d) 11Q& 18I#
e) None of these
2. What does ‘18I#’ stand for?
a) Feel
b) Another
c) Wind
d) is
e) None of these
3. What is the code for the word ‘Another ’?
a) 1N#
b) 15N*
c) 23J@
d) 18I#
e) Can't be determined
4. What is the code for the word ‘things’?
a) 4T&
b) 11I# 
c) 19O%
d) 4M$
e) Can't be determined
5. What is the code for the word ‘More’?
a) 4M$
b) 11I# 
c) 19O%
d) 4T&
e) Can't be determined
Directions (6 – 10): Study the following information carefully and answer the given questions:
A word arrangement machine when given an input line of words rearranges them following a particular rule in each step. The following is an illustration of input and various steps rearrangement.
Input: Initiative 13  Transportation  48 46 72  Personification Trigonometry  18 Thunderstorm  16  Intialization 
Step I: Thunderstorm Initiative 13 Transportation 46 72 Personification Trigonometry 18 16  Intialization 48
Step II: 72 Thunderstorm Initiative 13 Transportation 46 Personification Trigonometry 18 16 48 Intialization 
Step III: Transportation 72 Thunderstorm Initiative 13 46 Personification Trigonometry 16 48 Intialization 18
Step IV: 13 Transportation 72 Thunderstorm 46 Personification Trigonometry 16 48 Intialization 18 Initiative
Step V: Personification 13 Transportation 72 Thunderstorm Trigonometry 16 48 Intialization 18 Initiative 46
Step VI: 16 Personification 13 Transportation72 Thunderstorm 48 Intialization 18 Initiative 46 Trigonometry 
And Step VI is the last step of the arrangement as the desired arrangement is obtained. As per rules followed in the above steps, find out in each of the questions the appropriate step for the given input.
Input for the questions:
Communication 12 Authentication 15 36 Perfection Everything 53 Entertainment 28 41 Nationalization
6. What is the position of the word 'Perfection' in the 4th step?
a) Third from the left
b) Fourth from the right
c) Eighth from the left
d) Sixth from the left
e) None of these
7. How many steps will be required to complete the arrangement?
a) Three
b) Six
c) Five
d) Four
e) Seven
8. Which is the sixth element to the left of the fourth element from the right end in the second last step?
a) 36
b) Entertinment
c) 28
d) Perfection
e) Can’t be determined
9. What is the position of the word 'Nationalization' in the last step?
a) Third to the left
b) Fifth from the left
c) Sixth from the left
d) Eighth from the right
e) Eighth from the left
10. Which of the following steps will be the last but one? 
a) Fourth
b) Fifth
c) Sixth
d) Seventh
e) Eigth
Directions (11 – 12): Study the following information carefully and answer the question given below:
There are four boxes coloured i.e. Blue, Black, Red and White in which four types of cold drinks are stored. brands are Pepsi, Limca, Mirinda and Coca cola. Boxes are arranged in such a manner from top to bottom.
There are two boxes between Black colour box and Red colour box. The box in which Mirindra are stored is above Red colour box, but not immediate above. The box in which Limca is stored is immediate below white colour box, but not stored in Red colour box. Pepsi box is above the Coca cola box, but not immediate above Limca box.
11. In which of the following colour box, Pepsi is stored?
a) Blue colour box
b) White colour box
c) Red colour box
d) Black colour box
e) Either (a) or (b)
12. Which of the following drinks is stored in second lowest Box?
a) Pepsi
b) Coca – Cola
c) Mirinda
d) Limca
e) Can’t be determined
Directions (13 – 15): Study the following information carefully and answer the question given below:
In a State, the following signals are followed by its public:
 3 Red lights
 Stop
 2 Red lights
 Turn right
 1 Red light
 Turn Left
 3 Green light
 Go @ 60 kmph 
 2 Green lights 
 Go @ 40 Kmph 
 1 Green lights
 Go @ 80 kmph
Mr. Bhargava travels towards north and follows the given signals as:
Mr. Bhargava starts his journey by car when he sees 1 green light. He keeps driving and after an hour and reaches the first signal where he sees 1 red light and 2 green lights, he drives 15 minutes after noticing them and reaches the 2nd signal at which he sees 1 red light. From the second signal to the third signal he drives for 45 minutes. On reaching the 3rd signal he notices one light is red and three lights are green, but he continues driving for another 30 minutes. He now reaches the 4th signal where he notices equal number of red and green lights. When he drives further he recalls that at the 4th signal two lights were of red colour. After driving for 30 more minutes he sees 5th signal which is the last signal in his journey as he witnesses three red lights there.
13. What is approximate straight distance between the second signal and the end point?
a) 17 km
b) 65 km
c) 42 km
d) 58 km
e) 60 km
14. If the first signal after the starting point, is 2 Red lights and 2 Green lights, then what is the total distance covered by the man till the last signal ?
a) 175km
b) 195 km
c) 140km
d) 170km
e) 165km
15. In which direction is the starting point from the end point?
a) South-west
b) North-east 
c) North-west
d) South-east
e) None of these


Solutions:
(1 – 5): Explanation:  
In this question, 
1. Each of the symbols of mathematical operations in the end of the code represents the number of letters its corresponding word does have.
No. of letters in the word        Symbol
2                                                       *
3                                                       $ 
4                                                       #
5                                                      %
6                                                       &
7                                                      @
8                                                 ,     ^
Following the rule, the first code of the word 'Tomorrow' would be '^'.
2. Now, the letter used in the middle of the code is being codified in the following manner:
Take the first and the last letter of the word. Write down its position in number according to English alphabet. Calculate the sum of these two numbers and –
a. If the sum obtained is an even number, the code will be obtained by dividing it by 2 and finding the respective letter in alphabet on the same position.
b. If the sum obtained is an odd number, the code will be obtained by adding 1 to the sum, dividing the sum by 2 and finding the respective letter in alphabet on the same position.
For example, 
The word 'Tomorrow' starts with 'T' and ends with 'w'. These two letters take 20th and 23rd position in english alphabet respectively.
Sum of 20 + 23 = 43 (which is an odd number)
Dividing (43 + 1 =) 44 by 2 we get 22.
Now the letter at the 22nd position in alphabet is V.
So, the middle code for the word 'Tomorrow' obtained by applying the rule discussed  would be  V.
3. The number in each of the codes represents the position of first letter of a word in reserve alphabetical order - minus three.  
For instance,
'Tomorrow' starts with 'T' which is 7th in reserve alphabetical order
So the code for the word 'Tomorrow' be 7 - 3 = 4.
Hence, the complete code for 'Tomorrow' will be '4V^'.
Following the rules discussed so far, we can code the other words as well.
1. C)   2. A)   3. C)   4. A)   5. B)  
(6 – 10): Explanation:
In this Machine Input Output code, following changes are occuring in each of the steps:
In each step two changes are happening. One in the number and the other in word given.
Numbers are first getting reversed and are arranged as per their highest and lowest values.
Words are arranged according to the number of vowels in each word and the parity (the fact of being even or odd) of these numbers while prefering an odd numbered word prior to the even one. 
Step 1: The highest number obtained after the reversal of the given numbers is placed at the extreme right end and the lowest odd numbered vowel word is getting placed at the extreme left end.
Step 2: The lowest number obtained after the reversal of the given numbers is placed at the extreme left end and the highest even numbered vowel word is getting placed at the extreme right end.
Step 3. Now, second highest number obtained after the reversal of the given numbers is placed at the extreme right end and the second lowest odd numbered vowel word is placed at the extreme left end.
Step 4. Now, second lowest number obtained after the reversal of the given numbers is placed at the extreme left end and the second highest even numbered vowel word is getting placed at the extreme right end.
And so on ....  
Input: Communication 12 Authentication  15 36  Perfection  Everything  53  Entertainment  28  41  Nationalization
Step I: Everything Communication 12 Authentication 15 36 Perfection 53 Entertainment 41  Nationalization 28
Step II: 41 Everything Communication 12 Authentication 15 36 Perfection 53 Entertainment 28 Nationalization
Step II: Entertainment 41 Everything Communication 12 Authentication 15 53 Perfection 28 Nationalization 36
Step IV: 12 Entertainment 41 Everything Authentication 15 53 Perfection 28 Nationalization 36 Communication 
Step V: Authentication 12 Entertainment 41 Everything 53 Perfection 28 Nationalization 36 Communication 15
Step VI: 53 Authentication 12 Entertainment 41 Everything 28 Nationalization 36 Communication 15 Perfection
6. C)   7. B)   8. B)   9. E)   10. B)  
(11 – 12):
Table 
 Black 
 4 
Pepsi
White
3
Mirinda
Blue
2
Limca
Red
1
Cocacola
11. D)   12. D)  
(13 – 15):

13. D) Approximate distance between Second Signal and End point:
= √[(50)^2 + (30)^2] = √(2500 + 900) = √3400 = 58.30 = 58 km
14. D) Since only the direction of the man has changed, the total distance covered by Mr. bhargava will still remain the same.
Hence option D is correct.
Journey of Mr. bhargava can be tabulated as below:

Total distance= 80 + 10 + 30 + 30 + 20 = 170 km
15. A) From the above image we can clearly observe that the starting point is to the south-west with the reference of the end point