__Quantitative Aptitude Practice Questions for IBPS Clerk – Set 7__**Directions (1 – 5): In the following question, one or two equation(s) is/are given. You have to solve both the equations and find the relation between ‘x’ and ‘y’ and mark correct answer.**

(a) x > y

(b) x ≥ y

(c) x< y

(d) x ≤ y

**Directions (6 – 10): What should come in place of question mark (?) in the following number series?**

**6. 7, 35, 105, 525, 1575, 7875, ?**

(a) 39375

(b) 23625

(c) 11815

(d) 15750

(e) None of these

**7. 5120 1280 320 80 ?**

(a) 16

(b) 24

(c) 20

(d) 40

(e) None of these

**8. 117 389 525 593 627 (?)**

(a) 654

(b) 640

(c) 634

(d) 630

(e) None of these

**9. 16, 4, 2, 1.5, (?), 1.875**

(a) 4

(b) 1.875

(c) 1.5

(d) 2

(e) 1.75

**10. 2, 6, 14, 30, (?), 126**

(a) 62

(b) 98

(c) 87

(d) 113

(e) 97

**Directions (11 – 15): What approximate value will come in place of question mark (?) in the following question? (Note: – You are not expected to calculate the exact value)**

**11. 455.45 + 289.89 + 921.9 = 678.78 – ?**

(a) -988

(b) -862

(c) -781

(d) -908

(e) -912

**12. 74.68% of (24.77 × 7.89) + 665.59 =? – 110.91**

(a) 821

(b) 754

(c) 927

(d) 776

(e) 910

**13. (449.95 × 199.99 × 4501.23) ÷ (69.78 × 90.9 × 1449.85) = ?**

(a) 21

(b) 86

(c) 52

(d) 44

(e) 79

**Solutions:**

**1. E)**We will solve both the equations separately.

Comparing the values of x
and y, we get,

For x = -4, x ≤ y

But for x = - 2, x >
y, so relationship cannot be determined

**2. A)**As per the given data,

When x = -6 and y = -1,
then x < y

x = -6 and y = -2,
then x < y

x = -78 and y = -1,
then x < y

x = -78 and y = -2,
then x < y

From the above, we can
say x < y

**3. C)**As per the given data,

When x = -3/2 and y = 4,
then x < y

x = -3/2 and y = 3,
then x < y

x = -1 and y = 4,
then x < y

x = -1 and y = 3,
then x < y

∴ From the above, we can say x < y

**4. A)**As per the given data,

∴ x > y

**5. A)**As per the given data,

When x = 3 and y = -4,
then x > y

x = 3 and y = -8,
then x > y

x = 4 and y = -4,
then x > y

x = 4 and y = -8,
then x > y

∴ From the above, we can say x > y

**6. B)**The pattern of given series is:

→ 7,

→ 35 = 7 × 5,

→ 105 = 35 × 3,

→ 525 = 105 × 5,

→ 1575 = 525 × 3,

→ 7875 = 1575 × 5,

→ ? = 7875 × 3,

→ ? = 23625

**7. C)**The pattern of the given series is :

→ 5120,

→ 1280 = 5120/4,

→ 320 = 1280/4,

→ 80 = 320/4,

→ ? = 80/4,

→ ? = 20

**8. E)**In the given series, the difference between two consecutive numbers is as follows:

→ 389 – 117 = 272

→ 525 – 389 = 136

→ 593 – 525 = 68

→ 627 – 593 = 34

Hence it can be concluded
from the values of these differences that with every next term it reduces by exactly
half. i.e.

→ 272/2 = 136

→ 136/2 = 68

→ 68/2 = 34

∴ Next difference must be = 34/2 = 17

Now, let next number be
X. Then,

⇒X – 627 = 17

⇒ X = 644

Hence the required term
in given number series is

**644**.**9. C)**The pattern of the given number series is as following:

→ 16,

→ 16 × 0.25 = 4,

→ 4 × 0.5 = 2,

→ 2 × 0.75 = 1.5,

→ 1.5 × 1 = 1.5,

→ 1.5 × 1.25 = 1.875

Hence, the required term
in the given number series is 1.5

**10. A)**The pattern of the given number series is as following:

→ 2,

→ 2 × 2 + 2 = 6,

→ 6 × 2 + 2 = 14,

→ 14 × 2 + 2 = 30,

→ 30 × 2 + 2 = 62,

→ 62 × 2 + 2 = 126

Hence, the missing number
in the given number series would be 62,

**11. A)**455.45 + 289.89 + 921.9 = 678.78 – ?

? ≈ 679 – 455 – 290 – 922

? = – 988

**12. C)**74.68% of (24.77 * 7.89) + 665.59 =? – 110.91

75% of (25 * 8) + 666 =?
– 111

? = 75% of (25 * 8) + 666
+ 111

? = 150 + 777 = 927

**13. D)**(449.95 × 199.99 × 4501.23) ÷ (69.78 × 90.9 × 1449.85) = ?

? ≈ (450*200*4500)/
(70*91*1450)

? ≈ 44