# Quantitative Aptitude Practice Questions for IBPS Clerk – Set 2

Quantitative Aptitude Practice Questions for IBPS Clerk – Set 2
1. The sum of ages of George and Martin is 64 years. Five years back, the age of George was half of the age of Martin. Find the present age of Martin.
(a)  18 years
(b)  30 years
(c)  41 years
(d)  45 years
(e)  23 years
2. The ratio of three angles of a right angled triangle is 13 : 2 : 15. Find the measure of angle that is neither smallest nor largest (in °).
(a)  60
(b)  72
(c)  78
(d)  90
(e)  84
3. In a cricket tour, a 15 member team is taken. One of them is captain of team. Out of these fifteen, 11 get a chance to play. In how many ways can the playing team be selected if the captain always plays?
(a)  1365
(b)  3003
(c)  1001
(d)  364
(e)  1092
4. A train passes a man standing on a 154 m long platform in 5s. The train takes 12s to completely pass the platform. What is length and speed of the train?
(a)  24 m/s & 120 m
(b)  21 m/s & 105 m
(c)  22 m/s & 110 m
(d)  19 m/s & 95 m
(e)  None of these
5. The average temperature on Sunday, Monday and Tuesday was 45 °C and on Monday and Tuesday and Wednesday it was 42 °C. If on Wednesday it was exactly 40 °C, then on Sunday, the temperature was
(a)  42 °C
(b)  46 °C
(c)  49 °C
(d)  48 °C
(e)  45 °C
6. To form a mixture, 20 liters of milk and 7 liters of water are mixed together. Milk has a price of Rs. 54 per liter while water is available for free. What will be the price of 4 liters of resultant mixture?
(a)  Rs. 120
(b)  Rs. 144
(c)  Rs. 160
(d)  Rs. 180
(e)  Rs. 200
7. Two boys are running from the same place at the speed of 9 km/hr and 6 km/hr. find the distance between them after 9 minutes if they move in the opposite direction.
(a)  2250 m
(b)  2750 m
(c)  3250 m
(d)  2100 m
(e)  None of these
8. What is the difference between the simple interest and compound interest on a sum of Rs 7300 at the rate of 6 percent per annum in two years?
(a)  Rs 24.28
(b)  Rs 26.28
(c)  Rs 32.22
(d)  Rs 29.28
(e)  None of these
9. A, B and C invested Rs. 5000, Rs. 7000 and Rs. 6000, respectively in a business. If at the end of two years, they got a profit of Rs. 10,800, the share of B in profit is:
(a)  Rs. 4500
(b)  Rs. 4200
(c)  Rs. 1800
(d)  Rs. 1500
(e)  Rs. 3600
10. In Ritesh’s house, there are two pipes having the capacities to fill a tank in 20 and 24 minutes respectively and a faulty pipe which can empty the tank at a rate of 3 gallons per minute. If all the three pipes working together can fill the tank in 15 minutes, then find the capacity of the tank.
(a)  60 gallons
(b)  100 gallons
(c)  120 gallons
(d)  180 gallons
(e)  None of these
Directions (11 – 15): Given below is a table that shows technical features of some cars. Based on this information, answer the questions that follow.
 Car brand P Q R S Ground Clearance (in mm) 153 144 207 190 Mileage (in km/liter) 18 16 12 13 Engine capacity (in cc) 1200 1000 2000 1500
11. By what percentage is mileage of car P greater than average mileage of cars R and S?
(a)  32
(b)  40
(c)  44
(d)  50
(e)  56
12. The manufacturers of car S have decided to increase its engine capacity by 10% every year and decrease mileage by 10% every year. For how many years would the mileage and engine capacity of car S be less than that of car R?
(a)  0
(b)  1
(c)  2
(d)  3
(e)  4
13. The ratio of mileage and engine capacity is defined as longevity of a car. If a car is produced by taking average of given factors of all the cars, then what would be its longevity?
(a)  0.01136
(b)  0.01035
(c)  0.02118
(d)  0.03167
(e)  0.03254
14. By how many mm should the ground clearance of car Q should be increased so that its ground clearance becomes 15% more than that of P (in mm)?
(a)  28.75
(b)  23.39
(c)  27.75
(d)  31.95
(e)  30.5
15. Which car has a highest ratio of mileage to engine capacity?
(a)  P
(b)  Q
(c)  R
(d)  S
(e)  None of these

Solutions:
1. C) Sum of ages of George and Martin is 64 years.
Let George’s present age be T years
Martins present age = (64 T) years
Five years back, George’s age was half of Martin’s age
T 5 = 1/2 × (64 T 5) 2 × (T 5) = 64 T 5 2T - 10 = 59 – T 3T = 69 T = 23
Martins present age = 64 - T = 41
Martins present age is 41 years
2. C) The ratio of three angles of a right angled triangle is 13 : 2 : 15.
Let the angles be 13T, 2T and 15T.
Largest angle of a right angled triangle = 90°
15T = 90 T = 6
Measure of angle that is neither smallest nor largest = 13T = 13 × 6 = 78°
3. C) Out of 15 member team, 11 are to be selected in playing team.
Since captain will definitely be a part of playing team, our task reduces to selecting 10 players out of 14.
This can be done in 14C10 ways.
We know, nCr  nCn-r
14C10 14C14-10 14C4
Playing team can be selected in 14Cways, i.e. (14 × 13 × 12 × 11)/(4 × 3 × 2 × 1) = 1001.
4. C) Let the length of the train be x m and the speed be y m/s.
While crossing a man, train covers a distance equal to its own length.
x/y = 5
x = 5y
While crossing a platform, train covers a distance equal too its own length and length of platform.
length of train and platform together = (x + 154) m
(x + 154)/y = 12
x + 154 = 12y
5y + 154 = 12y    (Putting the value x = 5y)
y = 154/7 = 22
Length of the train = 5 × 22 = 110 m
Speed of the train = 22 m/s
5. C) We know, Average of quantities =sum of all quantities/no. of quantities
The average temperature on Sunday, Monday and Tuesday was 45 °C. Then total temperature of Sunday, Monday and Tuesday = 45° ×3 = 135°C
The average temperature on Monday and Tuesday and Wednesday it was 40 °C. Then total temperature of Monday and Tuesday and Wednesday = 42° ×3 = 126°C
As on Wednesday it was exactly 40 °C.Then total temperature of Monday and Tuesday = (126° – 40°)C = 86°C
The temperature of Sunday = total temperature of Sunday, Monday and Tuesday - total temperature of Monday and Tuesday = (135° - 86°)C = 49 °C
6. C) Price of resultant mixture = [Price of 20 lt milk + Price of 7 lt water]/(20 + 7)
Price of 4 liters of resultant mixture = 4 × [Price of 20 lt milk + Price of 7 lt water]/(20 + 7)
= 4 × [(20 × 54 + 7 × 0)/27] = 160
Price of 4 liters of resultant mixture is Rs. 160.
7. A) When they move in opposite direction,
Their relative speed = (9 + 6) km/hr = 15 km/hr
Time taken = 9 minutes = 9/60 hours
Distance covered = speed × time
Distance covered = (15 × 9/60) km
Distance covered = 9/4 = (9/4) × 1000 = 2250 m
8. B) We know that,
For 2 years, difference between S.I. and C.I. = P (R/100)^2
Where, P = principal and R = rate of interest
Required difference = (7300 × 36)/10, 000 = Rs 26.28
Hence, the required difference between simple and compound interest is Rs 26.28
9. B) Ratio of shares of A, B and C = Ratio of their investments for 2 years
= [(5000 × 2): (7000 × 2): (6000 × 2)] = [10000: 14000: 12000] = 5: 7: 6
Given: Net profit earned = Rs. 10,800
Bs share = Rs.7/18 × 10800 = Rs.4200
10. C) Let the faulty pipe can empty the tank in x hrs, then
Net part filled in 1 hr = 1/20 + 1/24 – 1/x = 1/15
1/x = 1/20 + 1/24 – 1/15 = (6 + 5 – 8)/120 = 3/120 = 1/40
By comparing both sides, we get x = 40.
The faulty pipe can empty the tank in 40 minutes.
Since rate of leakage = 3 gallons per minute
Volume of tank/rate of leakage = time taken by faulty pipe to empty the tank
Volume of the tank/3 = 40
Volume of the tank = 40 × 3 = 120 gallons
11. C) Average mileage of cars R and S = (12 + 13)/2 = 12.5
Percentage by which mileage of car P is greater than average mileage of cars R and S = [(18 – 12.5)/12.5] × 100 = 44
12. D) The manufacturers of car S have decided to increase its engine capacity by 10% every year and decrease mileage by 10% every year.
After 1 year, mileage of car S = 13 – 13 × (10/100) = 11.7
Since, the mileage will degrease further in coming years, it will always be less than that of car R.
After 1 year, engine capacity of car S = 1500 + 1500 × (10/100) = 1650
After 2 years, engine capacity of car S = 1650 + 1650 × (10/100) = 1815
After 3 years, engine capacity of car S = 1815 + 1815 × (10/100) = 1996.5
After 4 years, engine capacity of car S = 1996.5 + 1996.5 × (10/100) = 2196.5 > 2000
From end of first year to end of fourth year, mileage and engine capacity of car S will be less than that of car R, that is for a total of 3 years.
13. B) Average mileage of all cars = (18 + 16 + 12 + 13)/4 = 59/4 = 14.75
Average engine capacity of all cars = (1200 + 1000 + 2000 + 1500)/4 = 5700/4 = 1425
Longevity = Mileage/Engine capacity = 14.75/1425 = 0.01035
14. D) Suppose ground clearance of car Q is increased by T mm.
(144 + T) is 15% more than 153
144 + T = 153 + 153 × (15/100) = 175.95
T = 31.95
Ground clearance of car Q should be increased by 31.95 mm.
15. B) Ratio of mileage to engine capacity for car P = 18/1200 = 0.015
Ratio of mileage to engine capacity for car Q = 16/1000 = 0.016
Ratio of mileage to engine capacity for car R = 12/2000 = 0.006
Ratio of mileage to engine capacity for car S = 13/1500 = 0.0087
Clearly, the ratio is highest for car Q.