__Data Interpretation Practice Questions – Set 88__**Directions (1 – 5):**

**Study the graph carefully and answer the questions that follow:**

**Sale of automobiles (in thousands)**

**1. Decline in sales of LCVs was approximately what percent over the period?**

a) 4%

b) 5%

c) 3%

d) 6%

e) 7%

**2. Which of the following pairs showed growth over the period?**

a) HCV’s and LCV’s

b) Cars and Three-wheelers

c) Cars and Two-Wheelers

d) LCV’s and Cars

e) None of these

**3. Approximately what was the difference of percentage changes in sales of HCVs and three-wheeler sales over the given period?**

a) 14.0%

b) 4.5%

c) 23.5%

d) 28%

e) 36.5%

**4. What approximate per cent of growth did Cars have over the period?**

a) 4.5%

b) 8.5%

c) 5.0%

d) 2.5%

e) 3.0%

**5. Which of the following had the maximum decline in 1999-2000 as compared to 1998-1999?**

a) Three-Wheelers

b) HCV’s

c) LCV’s

d) Two-Wheelers

e) Cars

**Directions (6 – 10):**

**Study the following bar graph carefully to answer the questions.**

**Marks obtained By Five Students in Physics and Chemistry**

**6. What is the respective ratio between the total marks obtained by Q and S together in Chemistry to the total marks obtained by P and R together in Physics?**

a) 23 : 25

b) 23 : 21

c) 17 : 19

d) 17 : 23

e) None of these

**7. What is the respective ratio between the total marks obtained by P in Physics and Chemistry together to the total marks obtained by T in physics and Chemistry together?**

a) 3 : 2

b) 4 : 3

c) 5 : 3

d) 2 : 1

e) None of these

**8. Fill in the blank space in order to make the sentence correct as per the given information. Total marks obtained by T in both the subjects together is more than the marks obtained by…….**

a) Q in Chemistry

b) R in Physics

c) S in Chemistry

d) P in Physics

e) R in both the subjects together

**9. If the marks obtained by T in Physics were increased by 14% of the original marks, what would be his new approximate percentage in Physics if the maximum marks in Physics were 140?**

a) 57

b) 32

c) 38

d) 48

e) 41

**10. Marks obtained by S in Chemistry are what per cent of the total marks obtained by all the students in Chemistry?**

a) 25

b) 28.5

c) 35

d) 31.5

e) 22

**Directions (11 – 15):**

**Study the following graph carefully and answer the questions given below it.**

**A report on the amount of water (In Million litres) sold by six different companies:**

**Percentage of water sold by six different companies:**

**The amount of water (In million litres) sold over the years:**

**11. If the sale of the company A is increased by 5%, how many litres of water sold by the company A from 2010 to 2012?**

a) 3245000

b) 2646000

c) 2465000

d) 3524000

e) None of these

**12. If the company R has sold the water at Rs. 20/litre and the company B has sold the water at Rs. 18/litre in 2016, what is the difference between their turnover in that year?**

a) Rs. 824000

b) Rs. 762000

c) Rs. 672000

d) Rs. 726000

e) None of these

**13. What is the difference in the sale of water between the top 3 and bottom 3 companies in 2012?**

a) 198900 litres

b) 1889000 litres

c) 1898000 litres

d) 1988000 litres

e) None of these

**14. In 2014, the company with lowest sale of water sold the water at Rs. 16/litre and the company with highest sale of water sold the water at Rs. 22/litre, what would be the price of water per litre sold by company with lowest sale to equal the turn over with the company with highest sale?**

a) Rs. 63.25

b) Rs. 68.75

c) Rs. 54.50

d) Rs. 62.35

e) None of these

**15. What is the average amount of water sold by company B, K, and H in 2011?**

a) 150400 litres

b) 1054000 litres

c) 1504000 litres

d) 1045000 litres

e) None of these

**Solutions:**

**1. A)**Percentage Decline = (80800 – 77300)/80800 * 100 = 4.33% ≈ 4%

**2. B)**Since the growth in the sales of automobiles in 1999-2000 as compared to 1998-1999as seen in the bar graph, is for Cars and three-wheelers only

∴ Growth in the sales of cars in 1999-2000 as compared to
1998-1999 = 276000 – 262900 = 13100

∴ Growth in the sales of three-wheelers in 1999-2000 as
compared to 1998-1999 = 130000 – 122100 = 7900

**3. C)**∵ Number of HCVs sold in 1998-1999 = 80400

∵ Number of HCVs sold in 1999-2000 = 56200

∴ Percentage Change in the sales of HCVs = (80400 –
56200)/80400 * 100 = 30%

∵ Number of three-wheeler sold in 1998-1999 = 122100

∵ Number of three-wheeler sold in 1999-2000 = 130000

∴ Percentage Change in the sales of three-wheeler = (130000 –
122100)/122100 * 100 = 6.47%

∴ Difference of percentage changes in sales of HCVs and
three-wheeler = 30% - 6.47% = 23.53%

**4. C)**Percentage Growth = (276000 – 262900)/262900 * 100 = 4.98% ≈ 5%

**5. B)**Since it can be seen from the bar graph that decline in the sales of automobile is either for Two-wheelers, HCVs or LCVs in 1999-2000

∴ Decline in the sales of Two-wheelers in 1999-2000 = 1719300 – 1714000 = 5300

∴ Decline in the sales of HCVs in 1999-2000 = 80400 – 56200 = 24200

∴ Decline in the sales of LCVs in 1999-2000 = 80800 – 77300 = 3500

∴ Maximum decline is in the sales of HCVs in 1999-2000

**6. B)**Total marks obtained by Q and S together in Chemistry = (110 + 120)

= 230

Total marks obtained by P
and R together in Physics = (130 + 80)

= 210

Ratio between the total
marks obtained by Q and S together in Chemistry to the total marks obtained by
P and R together in Physics = 230 : 210

= 23 : 21

**7. D)**Total marks obtained by P in Physics and Chemistry together = (130 + 90)

= 220

Total marks obtained by T
in physics and Chemistry together = (50 + 60)

= 110

Ratio between the total
marks obtained by P in Physics and Chemistry together to the total marks
obtained by T in physics and Chemistry together = 220 : 110

= 2 : 1

**8. B)**Total marks obtained by T in both the subjects together = (50 + 60)

= 110

Marks obtained by Q in
Chemistry = 110

Marks obtained by R in
Physics = 80

Marks obtained by S in
Chemistry = 120

Marks obtained by P in
Physics = 130

Total marks obtained by R
in both the subjects together = (80 + 100)

= 180

Therefore,

Total marks obtained by T
in both the subjects together is more than the marks obtained by marks obtained
by R in Physics

**9. E)**Marks obtained by T in Physics = 50

If the marks obtained by
T in Physics were increased by 14% of the original marks

Then,

New marks of T in physics
= 50 + 14% of 50

= 50 + (14/100) × 50

= 50 + 7

= 57

Maximum marks in Physics =
140

Percentage of marks
obtained by T in physics = (57/140) × 100

= 40.71% ≈ 41%

**10. A)**Marks obtained by S in Chemistry = 120

The total marks obtained
by all the students in Chemistry = (90 + 110 + 100 + 120 + 60)

= 480

Percentage of marks
obtained by S in Chemistry to the total marks obtained by all the students in
Chemistry = (120/480) × 100

= 25%

**11. B)**From the pie - chart and line graph,

Percentage of water sold
by company A = 9

The sale of the company A
is increased by 5%.

So, the amount of water
sold by company A in 2010 = 5600000 × (14/100) = 784000 litres.

The amount of water sold
by company A in 2011 = 6200000 × (14/100) = 868000 litres.

And, the amount of water
sold by company A in 2012 = 7100000 × (14/100) = 994000 litres.

Hence, total amount of
water sold by company A from 2010 to 2012

= (784000 + 868000 +
994000) litres = 2646000 litres.

**12. B)**From the pie - chart and line graph,

The total amount of water
sold in 2016 = 12.7 million litres.

Percentage of water sold
by company R = 21

So, the amount of water
sold by company R in 2016 = 12.7 × (21/100) = 2.667 million litres.

The company R has sold
the water at Rs. 20/litre. So, the turnover of the company R in 2016

= Rs. 2667000 × 20 = Rs.
53340000 = Rs. 5.334 Crores.

And,

Percentage of water sold
by company B = 23

So, the amount of water
sold by company B in 2016 = 12.7 × (23/100) = 2.921 million litres.

The company R has sold
the water at Rs. 18/litre. So, the turnover of the company B in 2016

= Rs. 2921000 × 18 = Rs.
52578000 = Rs. 5.2578 Crores.

Hence, the difference
between their turnover in that year

= Rs. (5.334 - 5.2578)
Crores = Rs. 0.0762 Crores = Rs. 762000.

**13. D)**From the pie - chart and line graph,

The total amount of water
sold in 2012 = 7.1 million litres.

We can find the top 3 and
bottom 3 companies in sale of water from the percentage of water sold by
different companies.

Top 3 companies = B, K, R

Bottom 3 companies = A,
H, O

The amount of water sold
by top 3 companies in 2012 = 7.1 × (23 + 21 + 20)% = 7.1 × (64/100) = 4.544
million litres.

And, the amount of water
sold by bottom 3 companies in 2012

= 7.1 × (19 + 9 + 8) =
7.1 × (36/100) = 2.556 million litres.

∴ The difference in the sale of water between the top 3 and
bottom 3 companies in 2012

= (4.544 - 2.556) million
litres = 1.988 million litres = 1988000 litres.

**14. A)**From the pie - chart and line graph,

The total amount of water
sold in 2014 = 9.5 million litres.

We can find the company
with lowest and highest sale of water from the pie - chart.

Company with lowest sale
of water = H (8%)

Company with highest sale
of water = B (23%)

The amount of water sold
by company H in 2014 = 9.5 × (8/100) = 0.76 million litres.

The amount of water sold
by company B in 2014 = 9.5 × (23/100) = 2.185 million litres.

According to the
question, company B has sold water at Rs. 22/litre. So, the turnover of company
B

= Rs. (2.185 × 22)
millions = Rs. 48.07 millions.

∴ The required price of water per litre = Rs. (48.07/0.76) =
Rs. 63.25.

**15. B)**From the pie - chart and line graph,

The total amount of water
sold in 2011 = 6.2 million litres.

Percentage of water sold
by company B = 23

So, the amount of water
sold by company B in 2011 = 6.2 × (23/100) = 1.426 million litres

Percentage of water sold
by company K = 20

So, the amount of water
sold by company K in 2011 = 6.2 × (20/100) = 1.24 million litres

Percentage of water sold
by company H = 8

So, the amount of water
sold by company H in 2011 = 6.2 × (8/100) = 0.496 million litres

Then, the total amount of
water sold by these three companies in 2011

= (1.426 + 1.24 + 0.496)
million litres = 3.162 million litres.

Hence, the average amount
of water sold by company B, K, and H in 2011

= 3.162/3 = 1.054 million
litres = 1054000 litres.