Quantitative Aptitude Practice Questions for IBPS Exams (21 – 09 – 2017)

Mentor for Bank Exams
Quantitative Aptitude Practice Questions for IBPS Exams (21 – 09 – 2017)
1. In a class of 20 students, average mark obtained by them is 68. If the marks of two students were misread as 68 and 49 instead of the actual marks 86 and 60 respectively, what would be the correct average?
a)    78.5
b)    69.45
c)     59.5
d)    70
e)    66
2. For annual income in the slab of Rs. 1200000 to 2000000, a person pays tax at 20% over the surplus on Rs. 1200000. Sunil’s annual salary is Rs. 1500000. How much tax does he pays per annum?
a)    Rs. 300000
b)    Rs. 240000
c)     Rs. 120000
d)    Rs. 60000
e)    None of these
3. If Rs. 510 be divided among A, B, C in such a way that A gets 2/3rd of what B gets and B gets 1/4th of what C gets, then their shares are respectively :
a)    60, 90, 360
b)    135, 90, 285
c)     117.75, 78.5, 314
d)    110, 80, 320
e)    None of these
4. How much water must be added to 60 litres of milk at 1 ½ litres for Rs. 20 so as to have a mixture worth Rs. 10 2/3 a litre?
a)    10 litres
b)    12 litres
c)     15 litres
d)    18 litres
e)    None of these
5. A cistern can be filled by one pipe in 6 hrs, and by another in 5 hrs. There is a waste pipe also and if this is open when the 2nd pipe is working the cistern takes 7 ½ hrs. to fill. How long will the cistern take to fill if all the three pipes are open?
a)    1 1/2 hrs.
b)    3 1/3 hrs.
c)     6 1/2 hrs.
d)    8 1/3 hrs.
e)    None of these
6. If doubling a number and adding 20 to the results gives the same answer as multiplying the number by 8 and taking away 10 from the product, the number is
a)    5
b)    3
c)     4
d)    6
e)    None of these
7. Shanker started a business with an investment of Rs. 120000. After 3 months Awani joined him with Rs. 1,90,000. At the end of the year, they earned a profit of Rs. 17500. What is the share of Awani in the profit?
a)    Rs. 8000
b)    Rs. 8500
c)     Rs. 9000
d)    Rs. 9500
e)    None of these
8. A tradesman is marketing his goods 20% above the cost price of the goods. He gives 10% discount on cash payment, find his gain percent.
a)    12%
b)    8%
c)     15%
d)    18%
e)    None of these
9. Some amount out of Rs. 7000 was lent at 6% p.a. and the remaining at 4% p.a. If the total simple interest from both the fractions in 5 years was Rs. 1600, the sum lent at 6% p.a. was
a)    Rs. 2000
b)    Rs. 5000
c)     Rs. 3500
d)    Rs. 4500
e)    None of these
10. A person borrowed a sum on compound interest and returned it in 3 years in three equal installments of Rs. 133.10 each. If the rate of interest is 10%, find the sum borrowed.
a)    Rs. 331
b)    Rs. 332
c)     Rs. 350
d)    Rs.300
e)    None of these
11. A boat goes at the speeds of 10 km/h and 16 km/h in a river upstream and downstream respectively. Find the speed of the boat in still water.
a)    14 km/h
b)    19 km/h
c)     20 km/h
d)    13 km/h
e)    None of these
12. The average speed of a bus is 8 times the average speed of a bike. The bike covers a distance of 186 km in 3 hours. How much distance will the bus cover in 10 hours?
a)    4069 km
b)    4096 km
c)     4960 km
d)    4690 km
e)    None of these
13. A motor starts with the speed of 60 kmph with its speed increasing every two hours by 20 kmph. In how many hours will it cover 330 kms?
a)    1/4 hours
b)    4 1/2 hours
c)     4 hours 5 minutes
d)    Cannot be determined
e)    None of these
14. An express train 150m long is travelling with a speed of 36 km/hr. If a boy is cycling in the direction of train at 9 km/hr., the time taken by the train to pass the boy is:
a)    10 sec
b)    15 sec
c)     18 sec
d)    20 sec
e)    None of these
15. A is 30% more efficient than B. How much time will they, working together, take to complete a job which A along could have done in 23 days?
a)    11 days
b)    13 days
c)     20 3/17 days
d)    12 days
e)    None of these

Solutions:
1. B) Here, total number of students are 20. Initially, average mark obtained by them was 68.
Since Average marks = Total marks obtained by all students/number of students.
 So, total obtained marks by 20 student = Average marks × number of students.
Total marks = 68 × 20 = 1360
Now, since two marks were wrongly read, so we shall subtract wrong marks from total marks and then shall add actual marks in total marks to get correct total marks, i.e.
1360 – 68 – 49 + 86 + 60 = 1389.
Now, correct average = 1389/20 = 69.45

2. D) Given that a person should pay 20% tax over the surplus amount above Rs.1200000 for annual income in the slab of Rs. 1200000 to 2000000
Annual salary of Sunil = Rs. 1500000
The surplus amount above 12 lakhs = 1500000 1200000 = Rs.300000
We know that to express a% as a fraction, we have a% = (a/100)
The tax paid by Sunil per annum = 300000 × (20/100) = Rs.60000

3. A) According to the question,
A = 2B/3 and B = C/4
A/B = 2/3 and B/C = 1/4
To make the ratio common. Multiply B : C by 3 i.e. B : C = 3 : 12
A : B : C = 2 : 3 : 12
A’s share = 510 × 2/(2 + 3 + 12) = Rs.60
B’s share = 510 × 3/(2 + 3 + 12) = Rs.90
C’s share = 510 – 60 – 90 = Rs.360

4. C) Total worth of the milk is to remain same even after water is added [Assuming water is free]
Initially when there was 60 litres of milk and value of 20 per 1.5 litres,
 The total worth = (60/1.5) × 20 = Rs.800
Say now X litres of water is added
Final volume of mixture = 60 + X litres
This (60 + X) litres is valued at Rs.32/3 per litre
The total worth now = (60 + X) × (32/3)
Total worth is constant (60 + X) × (32/3) = 800
60 + X = (800 × 3)/32 = 75 X = 75 60 = 15 litres

5. B) Let the time taken by waste pipe to empty the cistern = t
Given waste pipe and 2nd pipe working together fill the cistern in 7.5 hours
2nd pipe working alone takes 5 hours to fill.
1/5 1/t = 1/7.5 1/15 =1/t t = 15 hours
1st pipe takes 6 hours to fill the cistern.
If all three are opened together then time taken = 1/[(1/6) + (1/5) – (1/15)] = 10/3
Time taken to fill the cistern = 3 1/3 hours

6. A) Let the number be x. According to the question,
2 × x + 20 = 8 × x – 10 2x + 20 = 8x 10 6x = 30 x = 5

7. D) We know that profit in a partnership is divided in the ratio of investment made × time of investment.
We have ratio of profit of Shanker and Ashwini as
1,20,000 × 12 : 1,90,000 × 9 12 × 12 = 19 × 9 12 × 4 : 19 × 3 48 : 57
Let share of Shanker be 48m.
Then share of Ashwini will be 57m
Hence, we have total share = 48m + 57m = 105m
We have 105m = 17500
m = 17500/105 m = 166.67
Hence share of Ashwini = 57m = 57 × 166.67 = 9500

8. B) Let the cost price of the goods be c.
Selling price = c + 20% of c
Selling price = 1.2 c
Now, he gives a discount of 10 %.
Final selling price = 1.2c 10% of 1.2c
Final selling price = 1.08c
Profit = Selling price – cost price
Profit = 1.08c – c
Profit = 0.08c
Profit % = (profit/Cost price) × 100%
Profit % = (0.08c/c) × 100%
Profit % = 8%

9. A) Formula, Simple interest = (P × R × T)/100
(Where P = Principal, R =Rate of interest per annum, T = Time in years)
Let the sum lent at 6 % p.a. be s
sum lent at 4 % p.a. = 7000 s
Simple interest at 6 % p.a for 5 years = (s × 6 × 5)/100 = 3s/10
Simple interest at 4 % p.a for 5 years == [(7000 – s) × 4 × 5)/100 = 1400 – (s/5)
  Total SI = 1400 – s/5 + 3s/10 = 1400 + (s/10)
Given in question, Total simple interest = 1600
1400 + s/10 = 1600 s/10 = 200 s = 2000

10. A) Given that,
Rate of interest R=10%
annual installment, X=Rs. 133.10
total number of instalments = 3


11. D) Speeds of the boat upstream and downstream are 10 km/h and 16 km/h respectively.
Speed of the boat in still water = (Speed in upstream + Speed in downstream)/2
= (10 + 16)/2 km/h = 26/2 km/h = 13 km/h

12. C) Let the average speed of the bus and the average speed of the bike be ‘V’ and ‘v’ respectively.
Given, V = 8v
The bike covers a distance of 186 km in 3 hours
So, v = 186/3 = 62 km/h
V = 8v = 8 × 62 = 496 km/h
Distance the bus will cover in 10 hours = 496 × 10 = 4960 km

13. B) According to the given information,
Speed of motor initially = 60 kmph
Distance travelled in 2 hours = 60 × 2 = 120 km
After 2 hours, speed of motor will become 60 + 20 = 80 kmph
Distance travelled in next 2 hours = 80 × 2 = 160 km
Total distance travelled = 120 + 160 km = 280 km (Still less than 330 km)
After 4 hours, speed of motor = 80 + 20 = 100 kmph
Distance to be travelled = 330 – 280 km = 50 km
Time required = Distance/Speed = 50/100 = 0.5 hour
Total time taken to cover 330 km = 4 + 0.5 hours = 4.5 hours

14. D) Relative velocity of the train = (36-9)km/hour = 27km/hour (Because the boy is going to the direction of train)
The train goes 27,000 m in 3600 seconds
The train goes 1 m in 3600/27000 seconds
The train goes 150m in (3600 × 150)/27000 = 20 seconds
The time taken to pass the boy is the time taken to cross the length of train, i.e. 20 seconds.

15. B) Time taken to complete the work for A alone = 23 days
Work done by A in one day = 1/23
Given A is 30% more efficient than B
A = 1.3 B
Work done by B in one day = (1/23)/1.3 = 1/30
Time taken for B alone to complete the work = 30 days
Work done in one day if they work together is = (1/23) + (1/30)
(1/23) + (1/30) = 53/690
Time taken to complete the work if they work together = 690/53 = 13 days
A and B can complete the work combine in 13 days