__Quantitative Aptitude Practice Questions | IBPS 2017__**Dear Aspirants,**

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**Mentor for Bank Exams**Quantitative Aptitude Quiz Section. The following quiz covers Inequalities (5 Questions), Data Sufficiency (5 Questions), Data Interpretation (5 Questions) and Word Problems (5 Questions). All the best for upcoming**IBPS Exams 2017.****Directions (1 – 5): In the following question two quantities are given Quantity 1 and quantity 2. By solving those quantities then give answer**

a) Quantity 1 ≥ Quantity 2

b) Quantity 1 = Quantity 2 (or) No
relation

c) Quantity 1 > Quantity 2

d) Quantity 1 ≤ Quantity 2

e) Quantity 1 < Quantity 2

**1. Quantity 1:**

**From a group of 5 male and 6 female, five persons are to be selected to form a committee so that at least 3 female are there in the committee. In how many ways can it be done?**

**Quantity 2:**In how many different ways can the letters of the word ‘QUANTITATIVE’ be arranged in such a way that the vowels always comes together? (Repetition not allowed)

**2. Quantity 1:**Three coins are tossed, what is the probability of getting at least two head?

**Quantity 2:**Two dice are thrown, what is the probability of getting sum of the two dice is multiple of 3?

**3. Quantity 1:**The ratio between Siva’s present age and Mala’s present age is 2:3. After four years their ratio will become 7:10, what is the age of Mala 10 years ago?

**Quantity 2:**The average age of 20 girls in a class is two-third of the boys in a class and the average age of 36 boys in the class is four-fifth of the girls in the class, approximately what is the average age of the class?

**4. Quantity 1:**In a village 20000 people are living of that 20% migrated to another village and 50% of migrated people are unemployed, what is the total number of people who were employed in the migrated people?

**Quantity 2:**According to the report of Municipality government population 20% increases every year compared to the previous year, what is the total population in the year 2016, if the population in the year 2018 is 3600?

**5. Quantity 1:**Vessel A contains milk and water in the ratio of 2:3 and vessel B contains Milk and Water in the ratio of 5:7, two vessels are mixed to make third vessel C, what percentage of water in the final mixture?

**Quantity 2:**There are two tanks P and Q having Alcohol and water in the ratio 1:4 and 3:5 respectively, two tanks mixed together and form a third tank S, what percentage of water in the final mixture?

**Directions (6 – 10): Each question below is followed by two statements A and B. You are to determine whether the data given in the statement is sufficient for answering the question. You should use the data and your knowledge of mathematics to choose between the possible answers.**

(a) If the statement A alone is
sufficient to answer the question, but the statement B alone is not sufficient.

(b) If the statement B alone is
sufficient to answer the question, but the statement A alone is not sufficient.

(c) If the statement A and B together
are needed to answer the question.

(d) If either the statements A alone
are statement B alone is sufficient to answer the question.

(e) If you cannot get the answer from
the statement A and B together, but need even more data.

**6. Is X an even number?**

**I.**X is divisible by 2.

**II.**(X +an odd number) is an odd number.

**7. What is the three digit number?**

**I.**one- third of that number is less by 27 of the half of that number.

**II.**One- fifth of that number is 20% of that number.

**8. The age of Tanish and Shivya are in the ratio of 6 : 5. What is the age of shivay?**

**I.**The age of Tanish and Danish are in the ratio of 3 :2.

**II.**After 6 years the ratio of Danish`s and Shivay`s age will be 6 : 7.

**9. In how many days 15 men can complete a piece of work?**

**I.**If 16 children can complete the same piece of work in 48 days.

**II.**If 9 men can complete the same piece of work in 27 days.

**10. What is the salary of C, in a group of A, B, C, D, E, and F whose average salary is ₹ 60, 000?**

**I.**Total of the salary of A and E is ₹ 64, 500

**II.**Total of the salary of B and F is ₹ 52, 600

**Directions (11 – 15): Study the following table and answer the questions that follow.**

**11. The incomes of companies X and Y in 2010 were in the ratio of 3 : 4 respectively. What was the respective ratio of their expenditures in 2010 ?**

a) 7 : 22

b) 14 : 19

c) 15 : 22

d) 27 : 35

e) 35 : 49

**12. If the expenditure of company Y in 2007 was Rs.220 crores, what was its income in 2007?**

a) Rs. 312 crores

b) Rs. 297 crores

c) Rs. 283 crores

d) Rs. 275 crores

e) Rs. 250 crores

**13. If the expenditures of companies X and Y in 2006 were equal and the total income of two companies in 2006 was Rs. 342 crores, what was the total profit of two companies together in 2006 ? (Profit = Income Expenditure)**

a) Rs. 240 crores

b) Rs. 171 crores

c) Rs. 120 crores

d) Rs. 102 crores

e) Rs. 150 crores

**14. The expenditure of company X in the year 2008 was Rs. 200 crores and the income of company X in 2008 was the same as its expenditure in 2011. What is the income of Company X in 2011 ?**

a) Rs. 385 crores

b) Rs. 465 crores

c) Rs. 335 crores

d) Rs. 295 crores

e) Rs. 250 crores

**15. If the incomes of two companies were equal in 2009, then what was the ratio of expenditure of Company X to that of Company Y in 2009?**

a) 6 : 5

b) 5 : 6

c) 11 : 6

d) 16 : 15

e) 20 : 11

**16. 14 men can do a work in 18 days, 15 women can do a work in 24 days. If 14 men work for first three days and 10 women work after that for three days, find the part of work left after that ?**

a) 3/4

b) 1/4

c) 1/2

d) 1/6

e) 1/5

**17. Perimeter of a rectangle is x and circumference of a circle is 8 more than the perimeter of the rectangle. Ratio of radius of circle and length of the rectangle is 1:2 and ratio of length and breadth of rectangle is 7:3. Find the length of the rectangle ?**

a) 14

b) 21

c) 28

d) 35

e) 7

**18. A invests on some scheme at 5% and B at 3% for two years. If the total sum invested by A and B is 4000 and the simple interest received by both is same then find the amount invested by A.**

a) Rs. 1,300/

b) Rs. 1,500/

c) Rs. 2,500/

d) Rs. 2,700/

e) Rs. 2,100/

**19. Two trains crosses each other in 14 sec when they are moving in opposite direction, and when they are moving in same direction they crosses each other in 3 min 2 sec. Find the speed of the faster train by what percent more than the speed of the slower train ?**

a) 16.67%

b) 17.33%

c) 16.33%

d) 17.67%

e) 18.33%

**20. A seller marks the price 50% above the cost price and gives 10% discount on an item. While selling, he cheats customer by giving 20% less in weight. Find his overall profit percent (approximate) ?**

a) 26%

b) 65%

c) 68%

d) 72%

e) 76%

**Solutions:**

**1. E)**From quantity 1, No. of ways = (

^{5}C

_{3}x

^{6}C

_{2}) + (

^{5}C

_{4}x

^{6}C

_{1}) + (

^{5}C

_{5}) = (10 * 15) + (5 + 6) + 1 = 150 + 11 + 1 = 162

From quantity 2, Number
of ways =7!/(2!×3!×2!)=210

Quantity 1 < Quantity
2

**2. C)**From quantity 1, total possibility =2

^{3}=8

Number of possibility =4

Required probability
=4/8=1/2

From quantity 2, total
possibility =6

^{2}=36
Number of possibility =12

Total probability
=12/36=1/3

Quantity 1 > Quantity
2

**3. C)**From quantity 1,

(2x+4)/(3x+4)=7/10

20x+40=21x+28
=>x=12 years

Mala’s present age
=3×12=36 years

Mala’s age 10 years ago
=36-10=26 years

From quantity 2,

(20×2/3×36+36×4/5×20)/(20+36)=(480+576)/56~
19 years

Quantity 1 > Quantity
2

**4. E)**From quantity 1,

Number of employee people
in the migrated =20000×20/100×50/100=2000

From quantity 2,

Number of people in 2018
=P(1+R/100)

^{n}
3600=P(1+20/100)

^{2}=> 3600×5/6×5/6=P
P = 2500

Quantity 1 < Quantity
2

**5. E)**From quantity 1,

Milk in vessel C
=2/5+5/12=(24+25)/60=49/60

Water in vessel C
=3/5+7/12=(36+35)/60=71/60

Milk and Water ratio in
vessel C =49/60:71/60=49:71

Required percentage
=71/120×100~ 59%

From quantity 2,

Alcohol in tank S
=1/5+3/8=20/40

Water in tank S
=4/5+5/8=(32+25)/40=57/40

Alcohol and Water in tank
S =23/40:57/40=23:57

Required percentage
=57/80×100~71%

Quantity 1 < Quantity
2

**6. D)**from statement A,

A number divisible by 2
is an even number.

From statement B,

2 + 3 = 5 (odd number)

4 + 9 = 13 (odd number)

**7. A)**from statement A,

Let the number be x.

(x/2)-(x/3)=27

= (3x-2x)/6=27

X = 27 × 6 = 162

Statement B is
superfluous.

**8. C)**from both statements,

T : S = 6 : 5

T : D = 3 : 2 = 6 : 4

∴ T : S : D = 6 : 5 : 4

Let the present age of
Danish and Shivay be 4x and 5x Years respectively.

∴ (4x+6)/(5x+6)=6/7

30x + 36 = 28x + 42

2x = 6

X= 3

Hence, the age of shivay
can be determined.

**9. B)**From statement B,

15 : 9 = 27 : x

15 × x = 9 × 27

X = (9×27)/15=81/5
days

**10. E)**from statement A,

A + E = 64500

From statement B,

B + F = 52600

∴ C + D = (A + B + C + D + E + F) – (A + B + E + F)

Hence, the age of C
cannot be determined.

**11. C)**ATQ, (x * 165)/(y * 150) = 3/4

=> x/y = (3 * 150)/(4
* 165) => x/y = 15/22

**12. B)**Let the income of company Y in 2007 = x

Profit percent = (I –
E)/E

35/100 = (x – 220)/220
=> 77 = x – 220 => x = Rs.297 crore

**13. D)**Let the expenditures of each of the companies X and Y in 2006 be Rs. x crores.

and let the income of
company X in 2006 be Rs. z crores

So that the income of
company Y in 2006 = Rs. (342 z) crores

Then, for company X we
have,

40 = (z – x)/x * 100
=> x = 100z/140 ……… (i)

Also, for company Y we
have

45 = (342 – z – x)/x *
100 => x = [(342 – z)/145] * 100 ….. (ii)

From equations (i) and
(ii), we get

100z/140 = [(342 – z) *
100]/145 => 5z/7 = (342 –z) * 4 * 7

On solving the above
equation we get z = 168

On substituting value of
z in eq (i) we get x = 120

∴ Total expenditure of companies X and. Y in 2006 =2 × 120 =
Rs. 240 crores

∴ Total profit = 342 – 240 = Rs. 102 crores

**14. B)**Let the income of company X in 2008 be x crores. Then,

55 = (x – 200)/200 * 100

∴ Expenditure of company X in 2011 = Income of company X in
2008 = Rs.310 crores

Let the income of company
X in 2011 be z crores.

Then,

50 = (z – 310)/310 * 100
=> z = 465

∴ Income of company X in 2011 = Rs.465 crores

**15. D)**Let the income of each of the two companies X and Y in 2009 be Rs. x.

and let the expenditures
of companies X and Y in 2009 be E1 and E2 respectively.

Then for company x, we
have

50 = (x – E1)/E1 * 100
=> 50/100 = (x/E1) – 1 => x = 150E1/100 ………. (i)

Also for company we have

60 = (x – E2)/E2 *100
=> 60/100 = (x/E2) – 1 => x = 160E2/100 …….. (ii)

From equations (i) and
(ii) we get,

150E1/100 = 160E2/100
=> E1/E2 = 16/15

Therefore required ratio
= E1 : E2 = 16 : 15

**16. A)**In 1 day 14 men will do = 1/18

In 3 days 14 men will do
= 1/6

In 1 days 15 women will
do = 1/24

In 3 days 15 women will
do = 1/8

In 3 days 10 women will
do = 1/8 * 10/15 = 1/12

Therefore remaining work
= 1 – 1/12 – 1/6 = 3/4

**17. C)**Let the length and breadth of rectangle be 7 a and 3 a respectively.

Perimeter of rectangle =2
(7a +3a)

x = 20 a

=> Radius of
circle/Length of rectangle = ½

r/7a = 1/2 => r = 7a/2

According to question,

2Пr – 20a = 8 => 2 *
22/7 * 7a/2 – 20a = 8

=> 2a = 8 => a = 4

**18. B)**Let the sum invested by A = Rs. x

and the sum invested by B
= Rs. 4,000 x

According to question,

(x * 5 * 2)/100 = [(4000
– x) * 3 * 2)]/100

=> 5x = 12000 – 3x
=> 8x = 12000

x = Rs.1500

Therefore Sum invested by
A = Rs.1500

**19. A)**Let the speed of slower train = a m/sec

and the speed of faster
train = b m/sec

We know that, T = D/S

14 = 1/(a + b) …….. (i)
and 182 = 1/(a – b) ……… (ii)

From equations (i) and
(ii)

14 (a + b) = 182 (a – b)

=> 14a + 14b = 182a –
182b

=> 168a = 196b =>
a/b = 7/6

Therefore, required
percentage = (7 – 6)/6 * 100 = 50/3 = 16.67%

**20. C)**Let the cost price be Rs. 100

Then marked price will be
Rs. 150

He gives 10% discount, so

Selling price = 150 *
90/100 = Rs.135

As he cheats and gives
20% less in weight,

cost price becomes = 100
* 80/100 = Rs.80

Profit percentage = (135
– 80)/80 * 100 ≈ 68%