__Data Interpretation Practice Questions – Set 87__**Directions (1 – 5): Below is given a pair of pie chart and bar graph representing number of students in different classes in a school in 2015 and growth in 2016. Based on this information, answer the questions that follow.**

**1. The students in 2016 in different classes are represented in a pie chart. What will be the difference between angles subtended by sectors representing 7**

^{th}and 9^{th}classes?(in°)
(a) 30

(b) 36.24

(c) 39.93

(d) 45

(e) 48.2

**2. If the increment in all the classes has only been in the form of girl students, then what will be the ratio of total number of boys and girls in 2016?**

(a) 43 : 41

(b) 23 : 27

(c) 8 : 9

(d) 2 : 3

(e) Cannot be
determined

**3. Instead of 20%, what should be the minimum growth in number of students for class 7**

^{th}, so that it does not have minimum number of students in 2016?
(a) 41.12

(b) 43.89

(c) 46.67

(d) 48

(e) 49.52

**4. What will be the average number of students in classes 8**

^{th}and 9^{th}taken together in 2015 and 2016?
(a) 164

(b) 171

(c) 177

(d) 183

(e) 189

**5. What should be growth in number of students for class 8**

^{th}in 2017 so that their number becomes same as number of students in class 9^{th}in 2016?
(a) 10%

(b) 12%

(c) 15%

(d) 8%

(e) 7.5%

**Directions (6 – 10): Study the table carefully and answer the following question.**

**The given table represents 10**

^{th}and 12^{th}class students reading different subject in a school.**6. What reading the difference between the number of 10**

^{th}class students reading English subject and the number of 12^{th}class students reading Math?
(a) 532

(b) 680

(c) 482

(d) 702

(e) None of
these

**7. Which subject has the maximum number of 10**

^{th}class students reading?
(a) Hindi

(b) Physics

(c) Chemistry

(d) Computer

(e) Economics

**8. The 10**

^{th}class students reading Hindi subject are how much percent more than 12^{th}class students reading Hindi subject?
(a) 35%

(b) 48%

(c) 75%

(d) 55%

(e) None of
these

**9. What is the approximate average number of 12**

^{th}class students reading subjects in English language?
(a) 572

(b) 463

(c) 372

(d) 562

(e) 509

**10. What is the difference between the number of 12**

^{th}students reading computer and the number of 10^{th }students reading economics?
(a) 432

(b) 558

(c) 468

(d) 238

(e) None of
these

**Directions (11 – 15):**

**Study the following graphs carefully and answer the questions that follow.**

**Percentage profit earned by two companies over the given years**

%
Profit = (Income – Expenditure)/Expenditure × 100

**11. If the total income of Company A in all the years together was equal to the total expenditure of Company B in all the years together, which was Rs. 265 lakhs, what was the total percentage profit earned by Company A for all the years together?**

(a) 45

(b) 37

(c) 52

(d) Cannot be
determined

(e) None of
these

**12. If the income of Company A in 1999 was equal to the expenditure of Company B in 2001, then what was the ratio of expenditure of Company A in 1999 to the income of Company B in 2001?**

(a) 25: 56

(b) 66: 25

(c) 10: 13

(d) 13: 10

(e) None of
these

**13. If the total expenditure of the two Companies in 2000 was Rs. 18 lakhs and expenditure of Companies A & B in that year were in the ratio of 4: 5 respectively, then what was the income of Company B in that year (in lakh)?**

(a) 8

(b) 10

(c) 10.4

(d) Cannot be
determined

(e) None of
these

**14. If the income of Company B in 1999 was Rs. 18.6 lakhs and ratio of incomes of Companies A % B in 1999 was 4: 3, What was the expenditure of company A in 1999 (in Rs. lakh)?**

(a) 12.5

(b) 14.5

(c) 15.5

(d) 16.5

(e) None of
these

**15. If the income of Company A in 1998 was equal to its expenditure in 2000, what was the ratio between Company’s expenditure in the years 1998 and 2000 respectively?**

(a) 3: 2

(b) 2: 3

(c) 1: 2

(d) Cannot be
determined

(e) None of
these

**Solutions:**

**(1 – 5): Explanation:**

Number
of students in class 6

^{th}in 2016 = 60 × (1 + 10/100) = 66
Number
of students in class 7

^{th}in 2016 = 45 × (1 + 20/100) = 54
Number
of students in class 8

^{th}in 2016 = 75 × (1 + 20/100) = 90
Number
of students in class 9

^{th}in 2016 = 90 × (1 + 10/100) = 99
Number
of students in class 10

^{th}in 2016 = 120 × (1 + 15/100) = 138**1. B)**∴ difference between angles subtended by sectors representing 7

^{th}and 9

^{th}classes = [(99 - 54)/(66 + 54 + 90 + 99 + 138)] × 360° = 36.24°

**2. E)**We do not have the original distribution of boys and girls in 2015. So, actual ratio cannot be determined neither for 2015 and nor for 2016 after increment.

∴ Ratio
cannot be uniquely determined.

**3. C)**To not have the minimum value, number of students for class 7

^{th}should be more than 66.

∴ Minimum
growth = [(66 - 45)/45] × 100 = 46.67%

**4. C)**∴ average number of students in classes 8

^{th}and 9

^{th}taken together in 2015 and 2016 ((75 + 90) + (90 + 99))/2 = 177

**5. A)**Suppose growth is T% for class 8

^{th}students in 2017.

⇒ 90 × (1 + T/100) = 99

⇒ T = (99/90
- 1) × 100 = 10

∴ Growth
should be 10%.

**6. B)**It is given that number of 10

^{th}class students reading English subject

=
9/13 × 1352 = 936

Number
of 12th class students reading Math’s = 1/4 × 1024 = 256

∴ Required
difference = 936 – 256 = 680

**7. B)**Given that, number of 10th class students reading Physics

=
4/7 × 2401 = 1372

Number
of 10

^{th}class students reading Chemistry = 2/3 × 729 = 486
Number
of 10

^{th}class students reading Hindi = 7/11 × 1331 = 847
Number
of 10th class students reading Computer = 7/10 × 1500 = 1050

Number
of 10th class students reading language = 4/13 × 2197 = 676

Number
of 10

^{th}class students reading Math = 3/4 × 1024 = 768
Number
of 10th class students reading Economics = 7/12 × 1728 = 1008

Number
of 10

^{th}class students reading English = 9/13 × 1352 = 936
Since,
the 10

^{th}class students are reading in maximum for Physics. Therefore this subject has the maximum percentage of 10^{th}class students.**8. C)**It is given that number of 10th class students reading Hindi = 7/11 × 1331 = 847

Number
of 12th class students reading Hindi = 4/11 × 1331 = 484

Therefore
required percentage = (847 – 484)/484 × 100 = 363/484 × 100 = 75%

**9. A)**Required Average = (1029 + 243 + 450 + 720 + 416)/5 = 2858/5 = 571.6 ≈ 572

**10. B)**According to question, number of 12

^{th}class students reading computer

=
3/10 × 1500 = 450

Number
of 10th class students reading economics = 7/12 × 1728 = 1008

∴ Required
difference = 1008 – 450 = 558

**11. D)**The answer can’t be determined. Because we need more data to solve this type of question.

We
don’t have the Expenditure of all over the year for company A that is essential
to solve this question.

**12. A)**Suppose Income of Company A in 1999 = X

Therefore
from the question, the expenditure of Company B in 2001 = X

Also
Expenditure of company A in 1999 = Y

And
Income of company B in 2001 = Z

⇒ 0.4 = Z/X
- 1

⇒1.4 = Z/X

⇒0.714 = X/Z

Ratio
between the Expenditure of company A in 1999 to income of company B in 2001 is

=
Y / Z

=
(Y/X) × (X/Z)

=
0.625 × 0.714 (∵
Substituting Values of Y/Z and X/Z))

=
0.446

=
25 / 56

**13. E)**The total expenditure of the two Companies in 2000 was Rs. 18 lakhs

Expenditure
of Companies A & B in that year were in the ratio of 4: 5

If
ratio factor is X lakhs then

Expenditure
of Company A = 4X lakhs

Expenditure
of Company B = 5X lakhs

Total
Expenditure = 18 lakhs

4X
+ 5X = 18

⇒ 9X =18

⇒ X = 2

Expenditure
of Company A = 4 × X = 4 × 2 = 8 lakhs

Expenditure
of Company B = 5 × X = 5 × 2 = 10 lakhs

Profit
percentage of company B in 2000 = 60 %

**14. C)**Income of Company B in 1999 was Rs 18.6 lakhs

Ratio
of incomes of Companies A and B in 1999 was 4: 3

Income
of company B in 1999 = 18.6 lakhs

Income
of company A in 1999/Income of company B in 1999 = 4/3

⇒ Income of
company A in 1999 = 4 × 18.6 /3

⇒ Income of
company A in 1999 = 24.8 lakhs

Profit
percentage of company A in 1999 = 60 %

⇒ 1.6 = 24.8
/ Expenditure of company A in 1999

⇒
Expenditure of company A in 1999 = 24.8 / 1.6

⇒
Expenditure of company A in 1999 = 15.5 lakhs

**15. B)**Percentage of profit of company A in 1998 is 50%

Percentage
profit earned by two companies over the given years

By
the formula we get,

⇒ 1.5 = Y/X

⇒ X/Y =
1/1.5

⇒ X/Y =
0.666

⇒X/Y = 2/3