Data Interpretation Practice Questions – Set 81
Directions
(1 – 5): Read the information given below and answer the questions followed:
Given below
is table which shows the ratio of efficiency of both A and B on different days and total time taken by A and B to complete
the work 1 if they complete whole work with the efficiency of different days.
There is also
the line graph which shows the time taken by B to complete work 2 if it
complete whole work with efficiency of different days.
Days

Efficiency of A and B

Time taken by both to complete work 1

Mon

3 : 2

3

Tue

3 : 2

4

Wed

7 : 9

6

Thr

8 : 9

5

Fri

5 : 4

8

1.
What is the ratio of time taken to complete work 1 by A alone if it complete
work with efficiency
of Monday to the time taken by A alone to complete work 2 if it complete work
according to efficiency of Friday.
A) 5 : 8
B) 2 : 3
C) 1 : 2
D) 7 : 8
E) 4 : 9
2.
Time taken by A alone to complete work 1 with efficiency as on Monday is what
percent of more or less than time taken to complete work 1 by B with efficiency as of Wednesday,
A) 55 (1/8)
B) 53 (1/8)
C) 53 (3/8)
D) 55 (3/8)
E) none of
these
3.
If A complete whole of work 1 according to efficiency of different days then
with efficiency of which day he
will complete work 1 in least time.
A) Monday
B) Tuesday
C) Wednesday
D) Thursday
E) Friday
4.
If they both decided to complete work 2 working alternatively starting from A
then in what time work will be complete. (They complete whole work 2 working
with eciency as of on Wednesday)
A) 13 2/10
B) 15 7/9
C) 16 7/9
D) 9 1/3
E) 27 1/2
5.
Number of days required by both to complete work 1 is what percent of number of
days required by both to complete work 2 (if they both complete the whole work
1 and work 2 with efficiency
of Thursday)
A) 2125/27%
B) 5300/23%
C) 2300/11%
D) 8000/23%
E) 10000/31%
Directions
(6 – 10): Read the given data carefully and answer the given question.
Total
Investment in thousand made by Abhimanyu and Arunoday is 6 different schemes (A, B, C, D, E, & F) is shown in bar
graph
Table shows
the ratio of investment of Abhimanyu and Arunoday.
Scheme

Ratio of Investments

A

11 : 14

B

7 : 13

C

1 : 1

D

2 : 3

E

3 : 7

F

2 : 3

6.
If scheme A offers
simple Interest at R% per annum and total interest obtained from schemes A for
2 years is 11200 then find
R% and share of interest of Abhimanyu
A) 8%, 4928
B) 6%, 7312
C) 5%, 5724
D) 8%, 5321
E) None of
these
7.
What is ratio of total investment of abhimanyu in scheme A, B and D together to
the total investment made in scheme C,E and F by Arunoday
A) 913 :
2222
B) 1652 :
1325
C) 1711 :
1820
D) Both a
& b
E) None of
these
8.
Average of investment made by Abhimanyu in scheme A, C is what % of average of investment
made by Arunoday in scheme E and F (Approximately)
A) 80%
B) 75%
C) 100%
D) 90%
E) 110%
9.
If scheme B and C offers simple interest at the rate of 10% and
100/3%respectively then find the total interest obtained from scheme B & C
in 3 year given that Abhimanyu withdraw his total amount from scheme B in 3rd
year whereas Arunoday withdraw his total amount in second year from scheme C.
A) 52520 Rs
B) 53373 Rs
C) 57225 Rs
D) 62250 Rs
E) None of
these
10.
What is the ratio of total amount invested by Abhimanyu to total amount
invested by Arunoday in all the schemes together except schemes E and F.
A)
2311/3189
B)
2225/1333
C)
1553/1120
D)
1852/2021
E) None of
these
Directions
(11 – 15): Study the following graph carefully to answer the given questions
Time taken by
the pipes to fill a tank/cistern (hours/minutes)
11.
A large cistern can be filled by two pipes P and Q. How many minutes will it
take to fill the Cistern from an empty state if Q is used for half the time and
P and Q fill it together for the other half?
A) 6.5
minutes
B) 7.5
minutes
C) 8.5
minutes
D) 9.5
minutes
E) None of
the Above
12.
Two pipes M and N can fill a tank. If both the pipes are opened simultaneously,
after how much time should N be closed so that the tank is full in 8 minutes?
A) 14
minutes
B) 12
minutes
C) 15
minutes
D) 18
minutes
E) None of
the Above
13.
Three pipe E, F, and R can fill a tank. If Pipe R alone can fill a tank in 24
minutes then the pipe R is closed 12 minutes before the tank is filled. In what
time the tank is full?
A) 8.(5/13)
B) 8.(4/13)
C) 7.(4/13)
D) 8.(6/13)
E) None of
these
14.
Two pipes C and D can fill a cistern. If they are opened on alternate minutes
and if pipe C is opened first, in how many minutes will the tank be full?
A) 4
minutes
B) 5
minutes
C) 2
minutes
D) 6
minutes
E) None of
the Above
15.
Two pipes, A and B are opened simultaneously and it is found that due to the
leakage in the bottom, 17/7 minutes are taken extra to fill the tank. If the
tank is full, in what approximate time would the leak empty it?
A) 27
minutes
B) 32
minutes
C) 36
minutes
D) 39
minutes
E) None of
these
Solutions:
1. A) Let time taken by to complete work 1 individually with efficiency of
Monday = 2x and 3x
So, 1/2x + 1/3x = 1/3 => 5/6x = 1/3 => x = 5/2
Let time taken by A & B to complete work 2 individually with efficiency of
Friday = 4x and 5x
Since 5x = 10 => x = 2 => 4x = 8
Required ratio = (2 * 5/2)/8 = 5 : 8
2. B) Time
taken by A to complete whole of work 1 with efficiency of Monday = 5 days
Time taken by B to complete whole of work 1 with efficiency of
Wednesday 9x, 7x
So 1/9x + 1/7x = 6 => 16/63x = 1/6 => x = 32/21
So, 7x = 7 * 32/21 = 32/3 days
Therefore required % = {[(32/3) – 5]/(32/3)} * 100 = 53 1/8%
3. A) Whole
work 1 completed by A with efficiency of Monday = 5 days
Whole work 1 completed by A with efficiency of Tuesday = 20/3 days
Whole work 1 completed by A with efficiency of Wednesday = 96/7 days
Whole work 1 completed by A with efficiency of Thursday = 85/8 days
Whole work 1 completed by A with efficiency of Friday = 72/5 days
4. B) B
complete work 2 with efficiency of Wednesday is 14
Let A and B complete work 2 individually working with efficiency of
Wednesday is 9x and 7x days
So, 7x = 14 => 9x = 18
First two day work of both = 1/14 + 1/18 = (9 + 7)/126 = 8/63
In 14 day part of work complete = 56/63
Remaining work = 1 – 56/63 = 1/9
A will complete 1/18 work on 15 day
Remaining will be complete by B on 16^{th} day ie 7/9 day
So total time = 15 7/9 day
5. A) Required
% = 5/(108/17) * 100 = 85/108 * 100 = 2125/27%
6. A) ATQ,
11200 = (70000 * R * 2)/100 => R = 8%
Share of Abhimanyu = 11/25 * 11200 = 4928
7. C) Required
ratio = [(11/25 * 70) + (7/20 * 65) + (2/5 * 80)]/[(1/2 * 60) + (7/10 * 40) +
(3/5 * 55)]
= (30.8 + 22.75 + 32)/(30 + 28 + 33)
= 85.55/91 = 1711 : 1820
8. C) Average of investment made by Abhimanyu in scheme A and C together is
=[( 11/25 * 70) + (1/2 * 60)]/2 = 60.8/2 = 30.4
Average of investment made in schemes E and F by Arunoday = [(7/10 * 40)
+ (3/5 * 55)]/2 = (28 + 33)/2 = 30.5
Required % = 30.4/30.5 * 100 ≈ 100%
9. C)
Interest obtained from scheme B = (7/20 * 65 * 20/100) + (13/20 * 65 * 30/100)
= 4.55 + 12.675 = 17225 Rs
Interest obtained from C = (½ * 60 * 3 * 1/3) + (1/2 + 60 * 3) = 30 + 10
= 40thousand
Therefore total interest = 177225 + 40000 = Rs.57225
10. A)
Required ratio = [(11/25 * 70) + (7/20 * 65) + (1/2 * 60) + (2/5 * 80)]/[(14/25
* 70) + (13/20 * 65) + (1/2 * 60) + (3/5 * 80)]
= (30.8 + 22.75 + 30 + 32)/(39.2 + 42.25 + 30 + 48)
= 115.55/159.45 = 2311/3189
11. B) Part
filled by P and Q = 1/15 + 1/10 = 1/6
Part filled by Q = 1/10
x/2(1/6 + 1/10) = 2/15 = 15/2 = 7.5 minutes
12. D) Required
time = y(1(t/x)) = 27(1(8/24))= 18 minutes
13. B) Let
T is the time taken by the pipes to fill the tank
(1/12 + 1/18 + 1/24)*(T – 12) + (1/12 + 1/18)*12 = 1
We will get T = 108/13 = 8 (4/13)
14. D) Pipe
P can fill = 1/12
Pipe Q can fill = 1/4
For every two minutes, 1/12 + 1/4 = 1/3 Part filled
Total = 6 minutes
15. D) Total
time taken by both pipes before the leak was developed = 60/7 minutes
now, leaks is developed which will take T time to empty the tank so,
(1/15 +1/20 – 1/T) = 1/11
solve for T, we will get 660/17 minutes = 39 minutes (approx.)