# Data Interpretation Practice Questions – Set 80

Data Interpretation Practice Questions – Set 80
Dear Aspirants,
Welcome to Mentor for Bank Exams. Data interpretation is quite different from the other fields tested in the Competitive examinations. Data interpretation or DI as the name suggests tests your ability to perceive data and use the data given to you in the most efficient manner. More practice is the only key for success in DI.
So here we have collected 3 sets of Data Interpretation Questions (Prelims Level) for your practice. Let the stop watch run in-front of you and solve the questions if your attempt for 10 questions correctly is more than 8 minutes then you are in danger zone and practice more DI Questions here.

Directions (1 – 5): Study the following pie chart and answer the questions given below.
Total number of students = 6800
1. What is the difference between the total number of students, who prefer beverage A and B together and the total number of students who prefer beverage D and F together?
a) 159
b) 95
c) 136
d) 952
e) 260
2. What is the ratio of the number of students who prefer beverage F to the number of students who prefer beverage A?
a) 3 : 11
b) 3 : 13
c) 6 : 11
d) 5 : 11
e) 6 : 13
3. The number of students who prefer beverage E and F together is what per cent of the total number of students?
a) 18%
b) 14%
c) 26%
d) 24%
e) 20%
4. The number of students who prefer beverage B is approximately, what per cent of the number of students who prefer beverage D?
a) 47%
b) 12%
c) 18%
d) 22%
e) 29%
5. How many students prefer beverage B and beverage E together?
a) 2312
b) 2313
c) 2315
d) 2318
e) 2320
Directions (6 – 10): Study the following graph carefully and answer the questions given below it.
A report on the no. of Android and Windows mobile users in a city over a certain time period:
No. of mobile users of two different operating systems:
Percentage of female mobile users of these two operating systems:
6. In which of the two years, the no. of female Android mobile users are equal in the given time period?
a) 2005 and 2007
b) 2008 and 2009
c) 2006 and 2007
d) 2007 and 2010
e) 2008 and 2010
7. The no. of female Windows mobile users is approximately what percent of the no. of female Android mobile users in 2006?
a) 32
b) 18
c) 27
d) 21
e) None of these
8. Find the difference between the no. of female Android and Windows mobile users in that year in which the percentage of female Android and Windows mobile users is equal?
a) 8200
b) 5400
c) 3600
d) 7200
e) None of these
9. What is the ratio between the no. of male Android and Windows mobile users in 2009?
a) 21 : 8
b) 12 : 17
c) 17 : 12
d) 23 : 15
e) None of these
10. What is the average no. of female Windows mobile users in 2005, 2007 and 2010?
a) 8680
b) 7950
c) 6260
d) 8260
e) None of these
Directions (11 – 15): Study the given bar-graph and answer the related questions.
The bar-graph represents the strength of employee in four departments on a company on during years 2011 – 2015.
11. What was percentage increase in department of HR employee in 2012 over 2013?
a) 16%
b) 25%
c) 22%
d) 32%
e) 8%
12. In which year, the strength of employee in department of accounts was minimum?
a) 2015
b) 2013
c) 2014
d) 2012
e) 2011
13. How many times was the total strength of the strength of employees in department of IT in 2011?
a) 4 times
b) 6 times
c) 3 times
d) 2 times
e) 2.75 times
14. What was the percentage of employees in department of operation in 2015?
a) 36%
b) 52.36%
c) 29%
d) 64.1%
e) None of these
15. What was the percentage of employee in department of HR in 2012?
a) 16.5%
b) 32%
c) 20.34%
d) 26%
e) 15.45%
Solutions:
1. C) Total number of students = 6800
Total students who prefer beverage A and B together (in degree angles) = 79.2° + 57.6° = 136.8°
Total students who prefer beverage D and F together (in degree angles) = 122.4° + 21.6° = 144°
360° represents 6800
Required difference = [(144° - 136.8°)/(360°)] × 6800 = 136
2. A) Total number of students = 6800
Students who prefer beverage A (in degree angles) = 79.2°
Students who prefer beverage F (in degree angles) = 21.6°
Required ratio = [((21.6°)/(360°)) × 6800]/[((79.2°)/(360°)) × 6800] = (21.6°)/(79.2°) = 3 : 11
3. D) Total number of students = 6800
Total students who prefer beverage E and F together (in degree angles) = 64.8° + 21.6° = 86.4°
360° represents 6800
Required percentage = (86.4°)/(360°) × 100 = 24%
4. A) Total number of students = 6800
Students who prefer beverage B (in degree angles) = 57.6°
Students who prefer beverage D (in degree angles) = 122.4°
Required percentage = (57.6°)/(122.4°) × 100 = 47.05% 47%
5. A) Total number of students = 6800
Students who prefer beverage B (in degree angles) = 57.6°
Students who prefer beverage E (in degree angles) = 64.8°
Total students who prefer beverage B and E together (in degree angles) = 64.8° + 57.6° = 122.4°
Total number of students = (122.4°)/(360°) × 6800 = 2312
6. B) From the line and bar graphs we get,
 Years No. of Android users (X) Percentage of female Android users (A) No. of female Android users = X × (A/100) 2005 45000 20 45000 × (20/100) = 9000 2006 50000 27 50000 × (27/100) = 13500 2007 40000 32 40000 × (32/100) = 12800 2008 60000 36 60000 × (36/100) = 21600 2009 72000 30 72000 × (30/100) = 21600 2010 76000 45 76000 × (45/100) = 34200
We can clearly observe that the no. of female Android mobile users are equal for the years 2008 and 2009.
7. C) From the line and bar graph,
The no. of Android mobile users in 2006 = 50000
Percentage of female Android mobile users in 2006 = 27
The no. of female Android mobile users in 2006 = 50000 × (27/100) = 13500
The no. of Windows mobile users in 2006 = 30000
Percentage of female Windows mobile users in 2006 = 12
The no. of female Windows mobile users in 2006 = 30000 × (12/100) = 3600
The required percentage = [(3600/13500) × 100]% = 26.66% ≈ 27%.
8. D) From the line and bar graph,
We can find the year in which the percentage of female Android and Windows mobile users is equal from the bar graph.
In 2008, the percentage of female Android and Windows mobile users is equal i.e. 36%.
The no. of Android mobile users in 2008 = 60000
Percentage of female Android mobile users in 2008 = 36
The no. of female Android mobile users in 2008 = 60000 × (36/100) = 21600
The no. of Windows mobile users in 2008 = 40000
Percentage of female Windows mobile users in 2008 = 36
The no. of female Windows mobile users in 2008 = 40000 × (36/100) = 14400
The difference between the no. of female Android and Windows mobile users in that year in which the percentage of female Android and Windows mobile users is equal = 21600 – 14400 = 7200.
9. A) From the line and bar graph,
The no. of Android mobile users in 2009 = 72000
Percentage of female Android mobile users in 2009 = 30
Percentage of male Android mobile users in 2009 = 100 – 30 = 70
The no. of male Android mobile users in 2009 = 72000 × (70/100) = 50400
The no. of Windows mobile users in 2009 = 32000
Percentage of female Windows mobile users in 2009 = 40
Percentage of male Windows mobile users in 2009 = 100 – 40 = 60
So, the no. of male Windows mobile users in 2009 = 32000 × (60/100) = 19200
The required ratio = 50400 : 19200 = 21 : 8.
10. B) From the line and bar graph,
 Years No. of Windows users (X) Percentage of female Windows users (A) No. of female Windows users = X × (A/100) 2005 20000 8 20000 × (8/100) = 1600 2007 35000 25 35000 × (25/100) = 8750 2010 45000 30 45000 × (30/100) = 13500
The total no. of female Windows mobile users in 2005, 2007 and 2010
1600 + 8750 + 13500 = 23850
The average no. of female Windows mobile users in 2005, 2007 and 2010
23850/3 = 7950
11. B) Number of employee in department of HR in 2012 = 120
Number of employee in department of HR in 2013 = 150
Required % = 30/120 × 100 = 25%
12. D) The strength of employee in department of accounts in 2011, 2012, 2013, 2014 and 2015 was 220, 80, 250, 200 and 150, respectively.
So, the strength of employee in department of accounts was minimum at 2012.
13. A) Total strength of employees in 2011 = 200 + 250 + 220 + 300 = 970
Strength of employees in department of IT = 250
Then, required number of times = 970/250 = 3.88 ≈ 4
14. E) Number of employee in department of operation in 2015 = 60
Total number of employee = 100 + 80 + 150 + 60 = 390
Required % = 60/390 × 100 = 15.38%
15. C) Number of employee in department of HR in 2012 = 120
Total number of employees in that year = 120 + 250 + 80 + 140 = 590
Required % = 120/590 × 100 = 20.34%