# Quantitative Aptitude Quiz for IBPS Exams 2017

Quantitative Aptitude Quiz for IBPS Exams 2017
Dear Aspirants,
Welcome to Mentor for Bank Exams IBPS Exams 2017 Quiz Section. The following quiz consists of Number Series (5 questions), Quadratic Equations (5 questions), Data Interpretation (5 questions), Word Problems (5 questions). All the best for upcoming IBPS Exams 2017.
Directions (1 – 5): Find the missing number in the following number series:
1. 4, 6, 15, ?, 236.25, 1299.375
A) 22.5
B) 37.5
C) 52.5
D) 67.5
E) 82.5
2. 263.25, 175.5, 117, 78, ? , 36
A) 48
B) 52
C) 54
D) 64
E) 71
3. 51, 62, 53, 60, ?, 58
A) 55
B) 42
C) 98
D) 75
E) 51
4. 125, 250, 286, ? , 693, 1422
A) 429
B) 550
C) 600
D) 629
E) 679
5. 212, ? , 339, 430, 542, 677
A) 197
B) 201
C) 254
D) 267
E) 327
Directions (6 – 10): In each of these questions, two equations (I) and (II) are given. You have to solve both the equations and give answer
(A) if x > y
(B) if x < y
(C) if x ≥ y
(D) if x ≤ y
(E) if x = y or there is no relation between ‘x’ and ‘y’.
Directions (11 – 15): Study the charts carefully and answer the related questions.
The pie-chart shows the cost price of six different articles sold by a store in 2015. The bar graph shows the profit % earned on six different articles.
11. The selling price of fan and cooler  together is approximately what percent of the selling price of T.V. and radio together?
A) 88%
B) 96%
C) 100%
D) 80%
E) 150%
12. The marked price of TV is what percent of the cost price of cooler ?
A)  35%
B) 40%
C) 22%
E) None of these
13. What is the difference between the selling price of LED and that of TV?
A)  1520.67
B) 26450
C) 3457.45
D) 2491.60
E) 1457.8
14. The selling price of fan is approx. what percent of the selling price of watch ?
A)  85%
B) 75%
C) 90%
D) 70%
E) 115%
15. The marked price of radio is approx. what percent of the selling price of LED if 20% discount is available on radio?
A)  55%
B) 51%
C) 45%
D) 36%
E) 44%
16. A vessel contain some litres of pure milk. If 25 litre of water is added to the vessel, then ratio between milk and water becomes 12:5, 17 litres of mixture is drawn from the vessel and 10 litre of water is added to the mixture. Find the new ratio between milk and water.
A) 8 : 5
B) 5 : 8
C) 6 : 5
D) 5 : 6
E) Can’t be determined
17. Ratio between heights of two cylinder in the ratio 3:5. Their volumes are in the ratio 27:80. Find ratio between their radius?
A) 9 : 16
B) 16 : 9
C) 3 : 4
D) 4 : 3
E) 9 : 20
18. A man invested a sum of money in Scheme A, at a rate of 15% per annum for simple interest, at the end of 2 years the amount received by him is invested in scheme B at 20% per annum for compound interest. If the interest received by him from scheme B at the end of 2 years is Rs. 2860, then find the sum invested by man in the beginning?
A) 3250
B) 5000
C) 6500
D) Can’t be determined
E) None of these
19. B is 20% more efficient than A. A started the work and work for x days and then A is replaced B. B completed the remaining work in x+8 days. Ratio of the work done by A and B is 2 : 3. In how many days A and B working together can complete the whole work?
A) 36 4/11
B) 36 7/11
C) 35
D) Can’t be determined
E) None of these
20. A and B started a business investing the money in ratio 4:6, after 6 months B withdraw his investment and C joins him with twice the amount of B. At the end of the year total profit is 3315. Find share of C?
A) 1530
B) 1535
C) 1695
D) 1655
E) None of these
Solutions:
1. C) The pattern of the series is ×1.5, ×2.5, ×3.5, ×4.5, × 5.5
2. B) The pattern of the series is number is multiplied with 2/3
3. A) The pattern of the series is +11, -9, +7, -5, +3
4. D) The pattern of the series is +5^3, +6^2, +7^3, +8^2, +9^3
5. D) The pattern of the series is +5×11, +6×12, +7×13, +8×14, +9×15
11. B) CP of fan = (12/100)*72000 = 8640
Profit% = 25%
SP of fan = (8640*125)/100 = 10800
CP of cooler = (18/100)*72000 = 12960
Profit% = 48%
SP of cooler = (12960*148)/100 = 19180.80
Total SP of fan and cooler together = 10800 + 19180.80 = 29980.80
CP of TV = (21/100)*72000 = 15120
Profit% = 42%
SP of TV = (15120*142)/100 = 21470.40
CP of radio = (10/100)*72000 = 7200
Profit % = 36%
SP of radio = (7200*136)/100 = 9792
Total SP of TV and radio = 21470.40 + 9792 = 31262.40
Required % = (29980.80/31262.40)*100 = 95.9% = 96%(approx.)
12. D) Since, we don’t have discount of TV. So, we can’t find the marked price.
13. D) CP of LED = (26/100)*72000 = 18720
Profit% = 28%
SP of LED = (18720*128)/100 = 23961.60
SP of TV = 21470.40
Required difference = 23961.60 – 21470.40 = 2491.20
14. A) CP of fan = (12/100)*72000 = 8640
Profit% = 25%
SP of fan = (8640*125)/100 = 10800
CP of watch = (13/100)*72000 = 9360
Profit % = 35%
SP of watch = (9360*135)/100 = 12636
Required % = (10800/12636)*100 = 85.47% = 85%
15. B) CP of radio = (10/100)*72000 = 7200
Profit% = 36%
SP of radio = (7200*136)/100 = 9792