Quantitative Aptitude Practice
Questions  IBPS 2017
Dear
Aspirants,
Welcome to Mentor for Bank Exams Quantitative
Aptitude Quiz Section. The following quiz covers Quadratic Equations (5
Questions), Simplifications (5 Questions), Data Interpretation (5 Questions)
and Word Problems (5 Questions). All the best for upcoming IBPS Exams 2017.
Directions (1 – 5): In the following question, two equations numbered I
and II are given. You have to solve both the equations and determine the
relation between x and y. Give answer,
a) x > y
b) x ≥ y
c) x < y
d) x ≤ y
e) x = y or
the relationship cannot be established.
1. I. 5x^{2 }– 18x + 9 = 0
II. 3y^{2} + 5y – 2 = 0
2. I. 6x^{ 2} + 13x + 5
=0
II. 3y^{2}+ 11y + 10 =0
3. I. 6x^{2} – 28x – 10 = 0
II. 3y^{2 }– 23y – 8 = 0
4. I. 8x^{2} + 6x = 5
II. 12y^{2} – 22y + 8 = 0
5. I. 10x^{2} – 33x – 7 = 0
II. 5y^{2} – 9y – 2 = 0
Directions (6 – 10): What value should come in place of question
mark (?) in the following questions? (Note: You are not expected to calculate
the exact value)
6. 92 × 576 ÷ 2√1296 = (?)^{3} + √49
a) 3
b) 9^{2}
c) 9
d) 27
e) None of these
7. (√8 × √8)^{(1/2)}+ (9)^{(1/2)} = (?)^{3} +
√8 – 340
a) 7
b) 19
c) 18
d) 9
e) None of these
8. (15 × 0.40)^{4} ÷ (1080 ÷ 30)^{4} × (27 ×
8)^{4}= (3 × 2)^{?+5}
a) 8
b) 3
c) 12
d) 16
e) None of these
9. (21% of 1326) – (17% of 932) = ?
a) 120.02
b) 206.05
c) 240.04
d) 120.20
e) None of these
10. (18% of 1024) + (26% of ?) = 486.96
a) 1164
b) 1248
c) 1324
d) 1150
e) 1162
Directions (11 – 15): Study the given table carefully and answer the
related question.
The
given table represents the employed and unemployed people and population of
seven rural areas of a district.
Seven Rural
areas

Employed :
Unemployed

Population

A

11 : 3

2856

B

17 : 13

4140

C

19 : 4

4600

D

9 : 7

3200

E

13 : 6

3800

F

8 : 3

3630

G

17 : 12

8410

11. If 40% of the unemployed people of rural area D are males, then what
is the number of unemployed females in area D?
a) 520
b) 680
c) 840
d) 720
e) None of these
12. What is the number of employed people in the area that has maximum
percentage of employed people?
a) 2346
b) 2640
c) 2244
d) 4930
e) 3800
13. By how much percent is the number of employed people in area F more
than the number of employed people in area A?
a) 26.24
b) 32.69
c) 37.14
d) 42.14
e) 17.64
14. What is the difference between the number of unemployed people of
area E and the number of employed people of area C?
a) 1200
b) 1400
c) 1600
d) 1800
e) 2600
15. If the ratio of males to females in G is 11: 18 and 65% females in G
are employed, then how many males of this rural area are employed?
a) 1537
b) 1706
c) 1804
d) 1932
e) None of these
16. A boat can travel 4.2 km upstream in 14 minutes. If the ratio of the
speed of the boat in still water to the speed of the stream is 7 : 1, how much
time will the boat take to cover 17.6 km downstream? (in minutes)
a) 52
b) 44
c) 48
d) 36
e) 54
17. A starts a business with a capital of Rs 1500. B joins the business
6 months after the start of the business and C joins the business 8 months
after the start of the business. At the end of the year their respective shares
in the profit was in ratio of 5 : 3 : 3. What is the sum of amount put in the
business by B and C together?
a) Rs 3300
b) Rs 3500
c) Rs 4200
d) Rs 4800
e) Rs 4500
18. The length of a rectangle is 4m more than the side of a square and
the breadth of the rectangle is 4m less than the side of the same square. If
the area of the square is 567 sq m, what is the area of the rectangle? (in sq
m)
a) 549
b) 545
c) 557
d) 559
e) 551
19. A sells an item to B at 20% profit. B sells it to C at 10% profit
and C sells it to D at Rs 116 profit. The difference between the cost price of
D and the cost price of A is Rs 500. How much did B pay to A for the item?
a) Rs 1240
b) Rs 1250
c) Rs 1440
d) Rs 1450
e) Rs 1400
20. 10 men can finish a piece of work in 15 days. 8 women can finish the
same piece of work in 25 days. Only 10 women started working and in a few days
completed a certain amount of work. After that 3 men joined them. The remaining
work was completed by 10 women and 3 men together in 5 days. After how many
days did 3 men join 10 women?
a) 11
b) 13
c) 15
d) 10
e) 12
Solutions:
1.
A) I. 5x^{2}18x +
9 = 0
⇒ 5x^{2} – 15x – 3x + 9 = 0
⇒ 5x(x – 3) – 3(x – 3) = 0
⇒ (x – 3)(5x – 3) = 0
Then, x = + 3 or x = + 3/5
II. 3y^{2} + 5y  2 = 0
⇒ 3y^{2} + 6y – y – 2 = 0
⇒ 3y(y + 2) – 1(y + 2) = 0
⇒ (y + 2)(3y – 1) = 0
Then, y =  2 or y = + 1/3
So, when x = + 3, x > y for y =  2 and x > y
for y = + 1/3
And when x = + 3/5, x > y for y =  2 and x >
y for y = + 1/3
∴ We can clearly observe that x > y.
2. C)
I. 3x^{2} + 5x – 2 =0
Or, 3x^{2} + 6x – x 2= 0
Or, 3x(x + 2) – 1(x + 2) =0
Or, (3x 1) (x +2) = 0
∴ X = 2, 1/3
II. 2y^{2} –
7y + 5 =0
2y^{2} – 2y – 5y + 5 = 0
Or, 2y(y – 1) – 5 (y – 1) =0
∴ y = 1, 5/2
Hence, x < y
3.
E) I. 6x^{2} –
28x – 10 = 0
⇒ 6x^{2} – 30x + 2x – 10 = 0
⇒ 6x(x – 5) + 2(x – 5) = 0
⇒ (x – 5)(6x + 2) = 0
Then, x = + 5 or x =  2/6 =  1/3
II. 3y^{2 }– 23y – 8 = 0
⇒ 3y^{2} – 24y + y – 8 = 0
⇒ 3y(y – 8) + 1(y – 8) = 0
⇒ (y – 8)(3y + 1) = 0
Then, y = + 8 or y =  1/3
So, when x = + 5, x < y for y = + 8 and x > y
for y =  1/3
And when x =  1/3, x < y for y = + 8 and x = y
for y =  1/3
∴ So, we can observe that no clear relationship
cannot be determined between x and y.
4.
D) I. 8x^{2} + 6x = 5
⇒ 8x^{2} + 6x – 5 = 0
⇒ 8x^{2} + 10x – 4x – 5 = 0
⇒ 2x (4x + 5) – 1(4x + 5) = 0
⇒ (4x + 5)(2x – 1) = 0
Then, x =  5/4 or x = + ½
II. 12y^{2}22y + 8 = 0
⇒ 6y^{2} – 11y + 4 =
0 [Dividing both sides by 2 ]
⇒ 6y^{2} – 8y – 3y + 4 = 0
⇒ 2y (3y – 4) – 1(3y – 4) = 0
⇒ (3y – 4)(2y – 1) = 0
Then, y = + 4/3 or y = + ½
So, when x =  5/4, x < y for y = + 4/3 and x
< y for y = + ½
And when x = + ½ , x < y for y = + 4/3 and x = y
for y = + ½
∴ We can clearly observe that x ≤ y.
5.
E) I. 10x^{2} – 33x – 7 = 0
⇒ 10x^{2} – 35x + 2x – 7 = 0
⇒ 5x(2x – 7) + 1(2x – 7) = 0
⇒ (2x – 7)(5x + 1) = 0
Then, x = + 7/2 or x =  1/5
II. 5y^{2} – 9y – 2 = 0
⇒ 5y^{2} – 10y + y – 2 = 0
⇒ 5y(y – 2) + 1(y – 2) = 0
⇒ (y – 2)(5y + 1) = 0
Then, y = + 2 or y =  1/5
So, when x = + 7/2, x > y for y = + 2 and x >
y for y =  1/5
And when x =  1/5 , x < y for y = + 2 and x = y
for y =  1/5
∴ So, we can observe that no clear relationship
cannot be determined between x and y.
6.
C) (?)^{3}+ √49 = 92 × 876 ÷ 2√1296
(?)^{3} + 7 = 92 × 576 ÷ 2 × 36
(?)^{3}+ 7 =92 × 576 ÷ 72
(?)^{3}+ 7 =92 × 8
(?)^{3}+ 7 =736
(?)^{3} = 7367 = 729
/ = ∛729
?=9
7.
A) (?)^{3} + √8 – 340 = (√8 × √8)^{(1/2)} +
(9)^{(1/2)}
(?)^{3} + √8 – 340 = √8 + 3
(?)^{3} = √8 + 3 – √8 + 340
(?)^{3} = 343
? = ∛343
? = 7
8.
B) (3 × 2)^{? + 5}
= (15 × 0.40)^{4} ÷ (1080 ÷ 30)^{4}×
(27 × 8)^{4}
(3 × 2)^{? + 5}= (6)^{4}÷ (36)^{4}×
(216)^{4}
(6)^{?+5=}(6)^{4}÷ (6^{2})^{4}×(6^{3})^{4}
(6)^{?+5=}(6)^{4} × (6)^{12}
? + 5 = 8
? = 8 – 5 = 3
9.
A) ? = (21% of 1326) – (17% of 932)
= 21% of 17 × 78 – 17% of 932
= 17% of (21 × 78 – 932)
= 175 of (1638 – 932)
= 17% of 706
= 120.02
10.
A) [1024 × (18 / 100)] + [? × (26 / 100)] =
486.96
=> [(18432 + 26 × ?) / 100] = 486.96
=> 26 × ? = 48696 – 18432 = 30264
∴? = (30264 / 26) = 1164
11.
C) Total population of area D = 3200
Number of unemployed people in area D = 7/(7 +
9) * 3200 = 7/16 * 3200 = 1400
∵ 40% of the unemployed people are males,
Number of unemployed females = 60% of 1400 = 60/100
* 1400 = 840
12.
E)
Clearly, area C has the maximum percentage of
employed people, and their number is 3800 in that area.
13.
E) Number of employed people in area F = 8/11 ×
3630 = 2640
Number of employed people in area A = 11/14 × 2856 =
2244
Required percentage = (2640 – 2244)/2640 * 100 =
17.64%
14.
E) Number of unemployed people of area E = 6/19
× 3800 = 1200
Number of employed people of area C = 19/23 × 4600 =
3800
∴ Required difference = 3800 – 1200 =
2600
15.
A) Population of G = 8410
Number of females in G = 18/29 × 8410 = 5220
Number of employed females = 65% of 5220 = 3393
Number of employed people in G = 17/29 × 8410 = 4930
Number of employed males in G = 4930 – 3393 =
1537
16.
B) Let the speed of the boat be 7x and that of
the stream be x.
Then, upstream speed = (7x – x) = 6x
And, downstream speed = 7x + x = 8x
Now, upstream speed = 4.2/14x60 = 18 kmph
So, 6x = 18
x = 3 kmph
Thus, speed of stream = 3 kmph
Downstream speed = 8 × 3 = 24 kmph
Time taken downstream to cover 17.6 km
^{17.6}/_{24}x60=
44 minutes
17.
E) Ratio of profits = 1500 × 12 : 6B : 4C : : 5
: 3 : 3
Capital of B = ^{(1500 x 12)}/_{6} x ^{3}/_{5} =
1800
Capital of C = ^{(1500 x 12)}/_{4} x ^{3}/_{5} =
2700
Amount of (B + C) = 2700 + 1500 = Rs 4500
18.
E) Side of square = 567 = 23.81
Length of rectangle = 23.81 + 4 = 27.81
Breadth of rectangle = 23.81 – 4 = 19.81m
Area of rectangle = 27.81 × 19.81 = 550.91 → 551m
19. C)
Let the cost price of A be Rs x. Then the cost
price of B will be 1.2x and the cost price of C will be 1.2x × 1.10 = 1.32x
Then the cost price of D = x × 1.2 × 1.10 + 116 = Rs
1.32x + 116
Now, 1.32x + 116 – x = 500
or, 0.32x = 500 – 116 = 384
x = ^{384}/_{32} x 100 =
1200
B’s cost price = 1200 × 1.2 = Rs 1440
Hence B paid to A Rs 1440.
20.
B) Ratio of men to women
(15 × 10)M = (25 × 8)W
or, 150M = 200W
or, 3M = 4W
W = ¾ M
1 man’s work = ^{1}/_{150}
(10W + 3M =) ^{21}/_{2} M
can do the work in
^{1}/_{150} x ^{21}/_{2} = ^{7}/_{100} days
^{65}/_{100} work
done by 10 women in (?) days.
8 women – 1 work – 25 days
10 women – ^{65}/_{100} work
in 25 x ^{8}/_{10} x ^{65}/_{100} =
13 days