__Percentages Practice Questions – Set 1__**1.**

**In an election between two candidates, 75% of the voters cast their votes, out of which 2% of the votes were declared invalid. A candidate got 9261 votes which were 75% of the total valid votes. Find the total number of votes enrolled in that election.**

a)
9000

b)
15680

c)
16800

d)
17200

**Answer: C)**

**Explanation:**

Let the number of votes enrolled be x. Then ,

Number of votes cast =75% of x. Valid votes = 98% of
(75% of x).

75% of (98% of (75%of x)) =9261.

[(75/100) * (98/100) * (75/100) * x] = 9261.

X = [(9261*100*100*100)/(75*98*75)] =

**16800.****2.**

**If the numerator of a fraction be increased by 15% and its denominator be diminished by 8%, the value of the fraction is 15/16. Find the original fraction.**

a)
5/4

b)
7/2

c)
8/3

d)
9/5

e)
None of these

**Answer: D)**

**Explanation:**

Let the original fraction be x/y.

Then (115% of x)/(92% of y)=15/16 =>
(115x/92y)=15/16

((15/16)*(92/115))=

**3/4****3.**

**In the new budget , the price of kerosene oil rose by 25%. By how much percent must a person reduce his consumption so that his expenditure on it does not increase ?**

a)
20%

b)
27%

c)
30%

d)
40%

e)
42%

**Answer: A)**

**Explanation:**

Reduction in consumption = [((R/(100+R))*100]%

[(25/125)*100]%=

**20%.****4. During one year, the population of town increased by 5% . If the total population is 9975 at the end of the second year , then what was the population size in the beginning of the first year ?**

a)
8000

b)
9700

c)
10000

d)
11500

e)
None of these

**Answer:**

**C)**

**Explanation:**

Population in the beginning of the first year

= 9975/[1+(5/100)]*[1-(5/100)] =
[9975*(20/21)*(20/19)]=

**10000.****5.**

**Shobha’s mathematics test had 75 problems i.e.10 arithmetic, 30 algebra and 35 geometry problems. Although she answered 70% of the arithmetic ,40% of the algebra, and 60% of the geometry problems correctly. she did not pass the test because she got less than 60% of the problems right. How many more questions she would have to answer correctly to earn 60% of the passing grade?**

a)
5%

b)
13%

c)
18%

d)
20%

e)
25%

**Answer: A)**

**Explanation:**

Number of questions attempted correctly=(70%
of 10 + 40% of 30 + 60% 0f 35)

=7 + 12+21= 45

questions to be answered correctly for 60% grade=60%
of 75 = 45

therefore required number of questions= (45-40) =

**5.****6.**

**How many kg of pure salt must be added to 30kg of 2% solution of salt and water to increase it to 10% solution?**

a)
9/4

b)
7/2

c)
8/3

d)
7/5

e)
None of these

**Answer: C)**

**Explanation:**

Amount of salt in 30kg solution =
[(20/100)*30]kg=0.6kg

Let x kg of pure salt be added

Then , (0.6+x)/(30+x)=10/100

==> 60+100x=300+10x

==> 90x=240 ==>

**x=8/3.****7.**

**Three candidates contested an election and received 1136, 7636 and 11628 votes respectively. What percentage of the total votes did the winning candidate get?**

a)
57%

b)
60%

c)
65%

d)
90%

e)
None of these

**Answer: A)**

**Explanation:**

Total number of votes polled = (1136 + 7636 + 11628)
= 20400.

Therefore, Required percentage = (11628/20400 x 100)
% =

**57%****8.**

**In an election between two candidates, one got 55% of the total valid votes, 20% of the votes were invalid. If the total number of votes was 7500, the number of valid votes that the other candidate got, was:**

a)
2700

b)
2900

c)
3000

d)
3100

e)
None of these

**Answer: A)**

**Explanation:**

Number of valid votes = 80% of 7500 = 6000.

Valid votes polled by other candidate = 45% of 6000

= (45/100 x 6000) =

**2700.****9.**

**A man sells an article at a profit of 25%. If he had bought it at 20 % less and sold it for Rs.10.50 less, he would have gained 30%. Find the cost price of the article?**

a)
14

b)
21

c)
33

d)
35

e)
None of these

**Answer: D)**

**Explanation:**

Let the C.P be Rs.x.

1st S.P =125% of Rs.x.= 125*x/100= 5x/4.

2nd C.P=80% of x. = 80x/100 =4x/5.

2nd S.P =130% of 4x/5. = (130/100* 4x/5) = 26x/25.

Therefore, 5x/4-26x/25 = 10.50 or x =
10.50*100/21=50.

Hence, C.P = Rs. 50.

**10. A marketing manager is able to manage an average of Rs240 per week during 40h week . But in the final week of the month, his rates are increased by 50%. Then find out the commission the marketing manager makes in that week, if he puts in 60h during that final week?**

a) 500

b) 540

c) 520

d) 600

e) None of these

**Answer: B)**

**Explanation:**

Average rate per hr = 240/40 = Rs6/hr

In last week, his rate per hour increases by 50%,

so in the last week, his hourly rate = Rs.6 x
(1+50%)= Rs.9

Total hour spent in final week = 60h

∴ Total commission = 60h x Rs.9/hr = Rs.540