__Reasoning Practice Questions for IBPS Clerk, IBPS RRB, IBPS PO__**Direction (1 – 5): Study the following information carefully and answer the given questions.**

**A number arrangement machine arranges two digit numbers in typical manner. The first step has been obtained by multiplying the digits in input. Multiplication has not been done in any other steps. They are obtained by applying certain logic. Each step is a resultant of previous step.**

**1. If each middle digit of all the three numbers in the step I are halved and then added, then what will be the final sum?**

a) 4

b) 6.5

c) 3.5

d) 7.5

e) None of
these

**2. If the final output is subtracted from ‘5’, then what will be the resultant value?**

a) -2.8

b) -3.2

c) 2.8

d) 3.2

e) None of
these

**3. Which of the following combination represent the first digit of the third number and second digit of the first number in step I of the given input?**

a) (5,2)

b) (8,3)

c) (3,8)

d) (2,5)

e) (2,4)

**4. Which of the following represent the difference between the third digit of the third number and second digit of the first number in step I?**

a) 4

b) 5

c) 6

d) -4

e) None of
these

**5. What is the multiplication of three numbers obtained in step II?**

a) 100

b) 120

c) 240

d) 220

e) None of
these

**Directions (6 – 10): In these questions, a relationship between different elements is shown in the statement(s). The statements are followed by four conclusions. Give answer for the following questions**

**6. Statements:**D> R< Y, V> W ≥ K = Y

**Conclusions:**

**I.**W> D

**II.**V ≤ Y

**III.**V> R

**IV.**K ≥ R

a) None
follows

b) Only III
follows

c) Only IV
follows

d) Only
either III or IV follows

e) None of
these

**7. Statement:**Q> N ≥ R = B ≤ L< J

**Conclusions:**

**I.**J> R

**II.**Q ≥ L

**III.**Q> B

**IV.**R> J

a) Only I and III follow

b) Only I
and IV follow

c) Only II
and III follow

d) Only II,
III and IV follow

e) None of
these

**8. Statement:**L = B ≥ Z = U< P = R

**Conclusions:**

**I.**L ≥ U

**II.**Z< R

**III.**B> R

**IV.**P> L

a) Only I
and III follow

b) Only I
and II follows

c) Only II
and III follow

d) Only II,
III and IV follow

e) None of
these

**9. Statements:**U ≥ R = C, C ≥ N> M

**Conclusions:**

**I.**R> N

**II.**U> M

**III.**R ≥ M

**IV.**N> U

a) None
follows

b) Only I
follow

c) Only II
follows

d) Only III
follows

e) Only IV
follows

**10. Statement:**E> D = G ≤ H ≤ I = L

**Conclusions:**

**I.**L> D

**II.**D = L

**III.**E> I

**IV.**L ≥ D

a) None
follows

b) Only III
follows

c) Only IV
follows

d) Only
either I or II and IV follows

e) None of
these

**Solutions:**

**(1 – 5):**

**In step I:**7* 5 = 35; 3*2 = 6;

5*
8 = 40; 6*1 = 6;

4*
7 = 28; 9*1 = 9;

**In step II:**each first digit and third digit of the numbers are added and then subtracted with second digit.

(6
+ 3) - 5 = 4; (6 + 4) - 0 = 10; (2+9) – 8 = 3;

**In step III:**divide the second number by the first number and also third number by second number.

10/4
= 2.5; 3/10=0.3;

**In step IV:**subtract the second number from first number. This is the final output.

2.5–
0.3 = 2.2

**1. B)**5/2 + 0/2 + 8/2 = 2.5 + 0 + 4= 6.5

**2. C)**The final output is ‘2.2’= 5 – 2.2 = 2.8

**3. D)**The first digit of the third number in step I is ‘2’ and the second digit of the first number is ‘5’. Hence, (2, 5)

**4. A)**The third digit of the third number in step I is ‘9’ and second digit of the first number in step I is ‘5’. Hence, 9 – 5 = 4

**5. B)**The two numbers obtained in step II are 4, 10 and 3

Hence,
4 *10*3 = 120

**6. B)**D> R< Y, V> W ≥ K = Y

W>
D not follows

V
≤ Y not follows

V>
R follows

K
≥ R not follows

**7. A)**Q> N ≥ R = B ≤ L< J

J>
R follows

Q
≥ L not follows

Q>
B follows

R>
J not follows

**8. B)**L = B ≥ Z = U< P = R

L
≥ U follows

Z<
R follows

B>
R not follows

P>
L not follows

**9. C)**U ≥ R = C, C ≥ N> M

R>
N not follows

U>
M follows

R
≥ M not follows

N>
U not follows

**10. D)**E> D = G ≤ H ≤ I = L

L>
D not follows

D
= L not follows

E>
I not follows

L
≥ D follows

Either
I or II and IV follows