__Numerical Ability Practice Questions for IBPS RRB (Set – 1)__**1. 45316 + 52131 – 65229 =? + 15151**

a) 17063

b) 17073

c) 17076

d) 17067

**2. (23 × 23 × 23 × 23 × 23 × 23)^5 × (23 × 23)^2 ÷ (23)^2 = (23)?**

a) 32

b) 30

c) 9

d) 7

e) 11

**3. (62.5 × 14 × 5) ÷ 25 + 41 = (?)^3**

a) 4

b) 5

c) 9

d) 8

e) 6

**4. (41+7×9)÷7+(25.153)=?**

a) 40

b) 23

c) 25

d) 35

e) None of
these

**5. 4 × 566 ÷ 5 + 24.2 – 36 = (?)^2**

a) 20

b) 21

c) 22

d) 23

e) 25

**6. If the square of a number is subtracted from 4052 and the difference is multiplied by 15, the answer so obtained is 41340. What is the number?**

a) 36

b) 1024

c) 32

d) 1296

e) None of
these

**7. The average of 20 numbers is zero. Of them, How many of them may be greater than zero, at the most?**

A) 0

B) 1

C) 20

D) 19

E) 21

**8. What is the least number which when divided by 5, 6, 7 and 8 leaves a remainder 3, but when divided by 9 leaves no remainder?**

A) 1108

B) 1683

C) 2007

D) 3363

E) 1997

**9. A man is 24 years older than his son. In two years, his age will be twice the age of his son. What is the present age of his son?**

A) 24 years

B) 23 years

C) 22 years

D) 21 years

E) 20 years

**10. The population of a town increased from 1,75,000 to 2,62,500 in a decade. What is the average percent increase of population per year?**

A) 4%

B) 5%

C) 6%

D) 7%

E) 50%

**Answers:**

**1. D) 2. A) 3. E) 4. A) 5. B)**

**6. A)**(4052 – x^2) × 15 = 41340 => x^2 = 4052 – 2756 = 1296 => x = 36

**7. D)**Average of 20 numbers = 0

=>
Sum of 20 numbers/20 = 0

=>
Sum of 20 numbers = 0

Hence
at the most, there can be 19 positive numbers.

(Such
that if the sum of these 19 positive numbers is x, 20th number will be ‘-x’)

**8. B)**LCM of 5, 6, 7 and 8 = 840

Hence
the number can be written in the form (840k + 3) which is divisible by 9.

If
k = 1, number = (840 × 1) + 3 = 843 which is not divisible by 9.

If
k = 2, number = (840 × 2) + 3 = 1683 which is divisible by 9.

Hence
1683 is the least number which when divided by 5, 6, 7 and 8 leaves a remainder
3, but when divided by 9 leaves no remainder.

**9. C)**Let the present age of the son = x years

Then,
present age of the man = (x + 24) years

Given
than, in 2 years, man’s age will be twice the age of his son

=>
(x + 24) + 2 = 2 (x + 2) => x = 22 years

**10. B)**Increase in the population in 10 years = 262500 – 175000 = 87500

Percentage
increase in the population in 10 years = 87500/175000 × 100 = 8750/175 = 50%

Average
percent increase of population per year = 50%/10 = 5%