Quantitative Aptitude Practice Problems for SBI PO

Mentor for Bank Exams
Quantitative Aptitude Practice Problems for SBI PO
1. Fares by bus and car are Rs.5 and Rs.14 per kilometer respectively. A man who travels 220 km spends Rs.2,270 in going a part of distance by bus and the remaining in car. How many kilometers did he travel in car?
a) 90
b) 75
c) 130
d) 80
e) None of these
2. The surface area of a sphere is same as the total surface area of a cylinder whose height is 4 cm and the diameter of the base is 8 cm. What will be the radius of the sphere?
a) 4.5 cm
b) 6 cm
c) 8 cm
d) 4 cm
e) None of these
3. Two pipes A and B fill a cistern in 16 minutes and 24 minutes respectively. When should be the second pipe B turned off so that the cistern may take 12 minutes to fill?
a) 8 minutes
b) 6 minutes
c) 5 minutes
d) 7 minutes
e) None of these
4. Production of a company in 2012 was 468 tonnes. If it increases by 15% in the first year and decreases by 8% in the second year, find the production of the company after two years?
a) 500.76
b) 493.875
c) 487.468
d) 495.144
e) None of these
5. The mean temperature of Monday to Wednesday was 39°C and of Tuesday to Thursday was 36°C. If the temperature on Thursday was 4/5th that of Monday, then what was the temperature on Thursday?
a) 45°C
b) 36°C
c) 36.5°C
d) 54°C
e) None of these
6. Harshita bought 20 pens, 8 packets of wax colours, 6 calculators and 7 pencil boxes. The price of one pen is 7, one packet of wax colour is 22, one calculator is Rs.175 and one pencil box is 14 more than the combined price of one pen and one packet of wax colours. How much amount did Harshita pay to the shopkeeper?
a) Rs.1,381
b) Rs.1,815
c) Rs.1,667
d) Rs.1,572
e) None of these
7. The average marks in English subject of a class of 24 students is 56. If the marks of three students were misread as 44, 45 and 61 of the actual marks 48,59 and 67 respectively, then what would be the correct average?
a) 56
b) 55
c) 57.5
d) 58.5
e) None of these
8. In a test, minimum passing percentage for girls and boys is 30% and 45% respectively. A boy scored 280 marks and failed by 80 marks. How many more marks did a girl require to pass in the test if she scored 108 marks?
a) 132
b) 140
c) 160
d) 112
e) None
9. Six-eleventh of a number is equal to twenty two percent of second number. Second number is equal to the one-fourth of third number. The value of the third number is 2400, what is the 45% of first number?
a) 107.6
b) 131.1
c) 115.4
d) 143.8
e) None of these
10. In an Entrance Examination Seema scored 56 percent marks, Nitya scored 92 percent marks and Meena scored 634 marks. The maximum marks of the examination are 875. What are the average marks scored by all the three girls together?
a) 1939
b) 817
c) 680
d) 643
e) None of these
Solutions:
1. C) Let the distance travelled by car be 'x' km
14x + 5(220 − x) = 2270
14x + 1100 − 5x = 2270
9x = 1170 x = 130
2. D) Surface area of a sphere = 4Пr2
 Total surface area of a cylinder = 2Пr(h + r)
Therefore 4Пr2 = 2Пr1(h + ra)
=> 4 × 22/7 × r2 = 2  × 22/7 × 4(4 + d) => r2 = 16 => r = 4
3. B) In 12 minutes first pipe completes = 12/16 = ¾
The remaining ¼ part filled by second pipe in ¼ × 24 = 6
Second pipe should be turned off after 6 minutes
4. D) Required production = 115% of 92% of 468 => 115/100 × 92/100 × 468 = 495.144
5. B)
6. C) C.P. of one pencil box = 7 + 22 + 14 = Rs.43
Total amount paid by Harshita = Rs.(20 × 7 + 8 × 22 + 6 × 175 + 7 × 43) = Rs.(140 × 176 + 1050 × 301) = Rs. 1667
7. E) Difference = 48 + 59 + 67 − 44 − 45 – 61 = 56
Correct average = 56 + 24/24 = 57
8. A) If the maximum marks of examination be x, then
(x × 45)/100 = 280 + 80 = 360 => x = (360 × 100)/45 = 800
30% of 800 = (800 × 30)/100 = 240 = Minimum marks to pass for girls
Therefore required difference = 240 – 108 = 132
9. E) Second number = 2400 × ¼ = 600
If the first number be x, then
x × 6/11 = 600 × 22/100 = 132 => x = (132 × 11)/6 = 242
Therefore 45% of 242 = 108.9
10. D) Total marks obtained by Seema = (875 × 56)/100 = 490
Total marks obtained by Nitya = (875 × 92)/100 = 805
Required average marks = (490 + 805 + 634)/3 = 1929/3 = 643