**Directions (1 – 5): In these questions, relationship between different elements is shown in the statements. These statements are followed by two conclusions.**

Give Answer

a) If only
Conclusion I is true

b) If only
Conclusion II is true

c) If either
Conclusion I or II is true

d) If neither
Conclusion I nor II is true

e) If both
conclusions I and II is true

**1. Statements:**H ≥ I = J > K ≤ L

**Conclusions:**

I. K < H

II. L ≥ I

**2. Statements:**S > C ≥ O, P < C

**Conclusions:**

I. O < P

II. S > P

**3. Statements:**A = B ≤ C, A > R

**Conclusions:**

I. B > R

II. R < C

**4. Statements:**D > E ≤ F, J < F

**Conclusions:**

I. D > J

II. E < J

**5. Statements:**P < Q > T, R ≥ Q

**Conclusions:**

I. R > P

II. T < R

**Directions (6 – 10): Answer the questions on the basis of the information given below.**

A number
arrangement machine when given an input of numbers/words, rearranges them
following a particular rule in each step. The following is an illustration of
input and steps of rearrangement.

**Input: dump 7 sat tin 8 5 born 9 pet 4**

Step 1: set
dump 7 tin 8 5 born 9 pet 4

Step 2: set
dump 7 tin 8 5 born 9 pet 61

Step 3: set pit
dump 7 tin 8 5 born 9 61

Step 4: set pit
dump 7 tin 8 born 9 61 52

Step 5: set pit
ton dump 7 8 born 9 61 52

Step 6: set pit
ton dump 8 born 9 61 52 94

Step 7: set pit
ton burn dump 8 9 61 52 94

Step 8: set pit
ton burn dump 9 61 52 94 46

Step 9: set pit
ton burn damp 9 61 52 94 46

Step 10: set
pit ton burn damp 61 52 94 46 18

This is the
final arrangement and step 10 is the last step for this input.

**Input: 11 pill but 9 5 ten 8 bat 7 doll**

**6. Which word/number is third to right of seventh element from right end in step 6?**

a) 94

b) bet

c) tin

d) 11

e) doll

**7. In step 4, if ‘tin’ interchanges position with ‘but’ and ‘11’ with ‘52’, then how many words are there in between ‘tin’ and ‘52’?**

a) none

b) one

c) two

d) three

e) more than three

**8. How many numbers/words are between ‘tin’ and ‘but’ in step 7?**

a) none

b) one

c) two

d) three

e) more than three

**9. What is the sum of the numbers which are fourth from left end and second from right end in step 5?**

a) 36

b) 47

c) 63

d) 49

e) 45

**10. What is the sum of digits of the sum of the numbers which are fourth from right end in step 9 and second from right end in step 6?**

a) 20

b) 9

c) 19

d) 11

e) 15

**Solutions:**

**1. A)**Conclusions

I. K <
H is True

II. L ≥ I is False

Only Conclusion
I is True hence answer is Option A.

**2. B)**Conclusions

I. O <
P is False

II. S >
P is True

Only Conclusion
II is True hence answer is Option B.

**3. E)**Given that, A = B ≤ C

and A > R

On combining
the statement we will get : R < A = B ≤ C

Conclusions

I. B >
R is True

II. R <
C is True

Both the
conclusions are True hence answer is Option E

**4. D)**Given that, D > E ≤ F

and J < F

On combining
the statement we will get : D > E ≤ F
> J

Conclusions

I. D >
J is False

II. E <
J is False

Both
Conclusions are False hence answer is
Option D

**5. E)**Given that, P < Q > T

and R ≥ Q

On combining
the statement we will get :

P < Q ≤ R
and R ≥ Q > T

Conclusions

I. R >
P is True

II. T <
R is True

Both
Conclusions are True hence answer is
Option E

**(6 – 10):**

If we see the
last step, it is found that changes are done in vowels as – a->e, e->I,
i->o, o->u and u->a. And also words in each step are taken according
to the sequence of vowels which is a, e, I, o, u

And for
numbers: Number are taking in ascending order, squared and digits reversed, so
4 => 4^2 = 16, become 61

Input: 11 pill
but 9 5 ten 8 bat 7 doll

Step 1: bet 11
pill but 9 5 ten 8 7 doll

Step 2: bet 11
pill but 9 ten 8 7 doll 52

Step 3: bet tin
11 pill but 9 8 7 doll 52

Step 4: bet tin
11 pill but 9 8 doll 52 94

Step 5: bet tin
poll 11 but 9 8 doll 52 94

Step 6: bet tin
poll 11 but 9 doll 52 94 46

Step 7: bet tin
poll dull 11 but 9 52 94 46

Step 8: bet tin
poll dull 11 but 52 94 46 18

Step 9: bet tin
poll dull bat 11 52 94 46 18

Step 10: bet
tin poll dull bat 52 94 46 18 121

**6. E) 7. B) 8. D)**

**9. C)**11 + 52 = 63

**10. D)**52 + 94 = 146, so sum of digits of 146 is 1 + 4 + 6 = 11