Quantitative Aptitude Quiz for SBI PO 2017
1. The combined age of husband and wife on their 20th wedding
anniversary was twice than it was at the time of wedding. If the husband is 3
years older than his wife. How old was he at the time of his marriage?
a) 29 years
b) 38.5 years
c) 21.5 years
d) 32 years
e) None of these
2. Sagar purchased 10 kg of rice at the rate of Rs. 15 per kg
and 25 kg of rice at the rate Rs. 14 per kg. He mixed the two and sold the
mixture. Approximately at what rate per kg should he sell the mixture to make
40 % profit in the transaction?
a) Rs. 20.00
b) Rs. 19.50
c) Rs. 15
d) Rs. 17.5
e) Rs. 22.5
3. The labeled price of a table is Rs. 7,500. The shopkeeper
sold it by giving 5% discount on the labeled price and earned a profit of 15%.
What approximately is the cost price of the table?
a) Rs. 5758
b) Rs. 6195
c) Rs. 6425
d) Rs. 7200
e) Rs. 6750
4. Two trains are traveling in the same direction at speeds of
50 kmph and 20 kmph respectively If the faster train passes the driver in the
slower train in 20 seconds, What is the length of the faster train?
a) 150 m
b) 149 m
c) 162 m
d) 166 m
e) None of these
5. A and B started a business in partnership. A invested Rs.
40000 for 6 months. A received Rs.6000 as his share out of the total profit of
Rs. 9000, What was the amount invested by B for the whole year?
a) Rs. 8000
b) Rs. 10000
c) Rs. 5000
d) Rs. 6500
e) None of these
6. A boat with speed 15 km/hr in standing water goes 30 km
downstream and returns in a total of 4.5 hours. What is the speed of current?
a) 4 kmph
b) 6 kmph
c) 5 kmph
d) 8 kmph
e) 7 kmph
7. Akash and Akshay are business partners. Akash invests Rs
35,000 for a period of 8 months and Akshay invests Rs 42,000 for a period of 10
months. Out of a total profit of Rs 31,570 what is Akash’s share?
a) Rs 12,420
b) Rs 18,040
c) Rs 18,942
d) Rs 12,628
e) Rs 16,248
8. Two pipes A and B can fill a cistern in 37.5 minutes and 45
minutes respectively. This cistern will be filled in half an hour if both the
pipes are opened together initially and pipe B is then turned off after X
minutes. What is X?
a) 10 minutes
b) 15 minutes
c) 12 minutes
d) 9 minutes
e) 13 minutes
9. 12 men and 18 boys working 7.5 minutes an hour complete a
particular piece of work in 60 hours. If a boy’s work is half as efficient as a
man’s work, how many boys will be needed to help 21 men to achieve twice the
work in 50 hours working 9 minutes in an hour.
a) 42
b) 46
c) 48
d) 38
e) 40
10. Presently a mixture in a tub contains substances A and B
in the ratio of 7:5. If 9 litres of this solution is drawn out and B is added
to the mixture in certain quantity the resulting mixture becomes 7:9. How much
litres of liquid A was kept in the tub initially?
a) 32
b) 20
c) 27
d) 21
e) 25
Solutions:
1. C) Let the
ages of husband and wife at the time of their 20th wedding anniversary be X
years and Y years respectively and X > Y.
Their combined age = (X + Y) years.
The ages of both husband and wife at
the time of wedding will be (X – 20) years and (Y – 20) years respectively.
Their combined age = (X – 20) + (Y –
20) = (X + Y – 40) Years
By first information, we have
(X + Y) = 2( X + Y – 40)
X + Y = 2X + 2Y - 80
Therefore, X + Y = 80-------A
and by second information, we have
X – Y =3 ----------------------B
Solving A and B, we get X = 41.5
years
Therefore, the age of husband at the
time of their 20th wedding anniversary X = 41.5 years
Age at the time of marriage = 41.5
years – 20 years = 21.5 years.
2. A)
Rice
variety
|
Quantity(Kg)
|
Rate(Rs/Kg)
|
Cost(in
Rs)
|
First
|
10
|
15
|
150
|
Second
|
25
|
14
|
350
|
Total
|
500
|
||
By 40% profit on cost price,
Selling price of mixture = 140/100 *
500 = Rs. 700
Therefore, selling price per kg of
mixture = 700/35 = Rs. 20
3. B) Labeled price = Rs. 7,500
By giving 5% discount on labeled
price, the selling price is = 95 / 100 * 7500 = Rs. 7125
By earning 15% profit on the selling
of price Rs. 7125 the cost price is = 100 / 115 * 7125 = Rs. 6195.65
Therefore, approximate cost is 6195.65
4. D) Given :
Speed of fast train = 50 kmph.
Speed of slow train = 20 kmph.
The driver in the slower train is
moving with the speed of the slower train which is 20 kmph.
The faster train will pass the driver
when it has gained a distance. Distance gained by faster train
in 1 hour = (50 – 20) = 30 km = 8.33 m/sec
Distance gained by faster train in 20
sec = 20 * 8.33 = 166.6 m.
Therefore, Length of faster train =
166.6 m.
5. B) Profits of A and B are distributed
in the same ratio of their investment and period of investments.
Investment of A/ Investment of B =
Profit of A/ Profit of B = 6000/3000
(40000*1/2)/X*1 = 2/1
Therefore, X = B's investment amount
= Rs. 10,000.
6. C) Speed of the boat in still water: 15
km/hr
Speed of boat downstream: (15+x)km/hr
where x is speed of the current.
The boat travels 30 km downstream and
then 30 km upstream and takes 9/2 hours.
Total time= Time taken to travel
downstream + Time taken to travel upstream
=> 4/5= (30/(15+x))+(30/(15-x))
=>x= 5
7. C) For a given business profit is
directly dependent upon the capital invested and the time of investment.
=> Ratio of shares of Akash and
Akshay becomes: (35,000*8)/(42,000*10) = 2/3
=>% of profit belonging to Akash:
2/(3+2)*(31,570)
=>Rs 12,768
8. D) Let B be turned off after X minutes.
Part of water will be filled by A + B
in x minutes + After tap B is closed rest filled by A in (30-x) minutes = 1
=> x/(time taken to fill the
container by each separately) + 30 - x/(time taken to fill the container by A
alone) = 1
=> x(2/75 + 1/45) + (30-x)2/75 = 1
=> 11x + 180 – 6x = 225
Therefore, x = 9 minutes
9. A) 1 man is equivalent to 2 boys in work
capacity. 12 men + 18 boys = 12 x 2 + 18 = 42 boys.
Let the required number of boys be x.
So Total number of people doing work = 21 men x 2 (according to work capacity)
+ x boys.
Taking respective ratios as required:
Given:
=> Hours 50:60
=> Minutes per hour 9: 15/2
=> Work 1:2
=> People: 42: 42 + x
=> 50 x 9 x 1 x (42+x) = 60 x 15/2
x 2 x 42
=> 42 +x = 84
x = 42
10. D) Currently the mixture is in ratio of
A/B: 7:5
=> This means fraction of A in the
solution: 7/12
=> Fraction of B in the solvent:
5/12
=>New concentration of A=
7-(7/12)9
=>New concentration of B=
5-(5/12)9+x
=> (7-(7/12)9)/(5-(5/12)9+x) = 7/9
=>x=21
